Posted by idcm@drupal.org on August 10, 2009 at 1:19pm
I am not sure if this is an appropriate discussion topic to post here. If not, my apologies. I saw how others had posted views arguments solutions here and thought if I could get this resolved, it would make a nice addition to the dojo.
I just created a forum help request on D.O at http://drupal.org/node/544884 and was wondering if anyone was familiar with the challenge of passing a URL argument to a view block.
I look forward to any advice you can share.
Thanks
c
Categories: Arguments, views, Code development, Discussion, Coffeetalk, or BOF, views
Comments
This has been resolved. See
This has been resolved. See http://drupal.org/node/544884 for resolution.
I am going to write this up and share, just not right now. Gotta get back on schedule. The key points are:
c
Cindy McCourt
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passing argument to view block get 404
Hello,
I have the same problem please help me...
druapal 6, IIS6, no clean urls
here is my situation:
basically, i want to create a normal page but at the bottom it should list all my ingredients.
next to my list I want to have a links as: A-e E-F and so on to filter my list when the user clicks on it.
here is what i have done:
I have created a content type: ingredients
I have created a taxonomy vocabulary with A-e E-F ... terms
I have created a views to list all my gradients
i have created the my view as a block
set the view argument as:
taxonomy: term
Action to take if argument is not present: > phpcode:
$path = drupal_get_path_alias( $_GET["q"]);
$path = explode("/", $path);
return $path[1];
Action to take if argument does not validate: Display All Values
when I click on my A-e link for example with this url: index.php?q=ingredients/A-E
i get 404 page
if I return "A-E" works fine...
also it works perfectly if i create the view as a page... but i need it as a block anyway
am I missing something? please help me...
sh