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Assert.Equal(0.0, (double)unitary.Data[1, 0, 1], precision: 6);
Assert.Equal(1.0, (double)unitary.Data[1, 1, 1], precision: 6);
Assert.Equal("Real:\n[[1.0000000000000002, 0], \n[0, 0]]\nImag:\n[[0, 0], \n[0, 1.0000000000000002]]", unitary.ToString());
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Why are the array dimensions different between implementations?
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The previous implementation uses a 3 dimensional matrix of floating-point values to represent a two-dimensional matrix of complex numbers (the extra dimension is used to represent the real and imaginary parts of the values).
The new implementation uses a two dimensional matrix of complex values (internally it uses a one-dimensional list to store everything).
billti
Bill Ticehurst (billti)
approved these changes
Dec 6, 2022
Robin Kuzmin (kuzminrobin)
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Jan 12, 2023
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/azp where
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This refactors some code that deals with unitary matrix to drop the NumSharp dependency.