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121. Best Time to Buy and Sell Stock #21
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59 changes: 59 additions & 0 deletions
src/0121_best_time_to_buy_and_sell_stock/maxprofit.go
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/* | ||
121. Best Time to Buy and Sell Stock | ||
https://leetcode.com/problems/best-time-to-buy-and-sell-stock/ | ||
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Say you have an array for which the ith element is the price of a given stock on day i. | ||
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If you were only permitted to complete at most one transaction | ||
(i.e., buy one and sell one share of the stock), design an algorithm to find the maximum profit. | ||
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Note that you cannot sell a stock before you buy one. | ||
*/ | ||
// time: 2018年12月28日 | ||
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package maxprofit | ||
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// dynamic programming | ||
// for every price, find the max profit, then record the current minimum price. | ||
// time complexity: O(n) | ||
// space complexity: O(1) | ||
func maxProfit(prices []int) int { | ||
n := len(prices) | ||
if 0 == n || 1 == n { | ||
return 0 | ||
} | ||
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var ( | ||
res int | ||
minPrice = prices[0] | ||
) | ||
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for _, price := range prices { | ||
if price - minPrice > res { | ||
res = price - minPrice | ||
} | ||
if price < minPrice { | ||
minPrice = price | ||
} | ||
} | ||
return res | ||
} | ||
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// brute force | ||
// time complexity: O(n^2) | ||
// space complexity: O(1) | ||
func maxProfit1(prices []int) int { | ||
n := len(prices) | ||
if 0 == n || 1 == n { | ||
return 0 | ||
} | ||
res := 0 | ||
for i := 1; i < n; i++ { | ||
for j := 0; j < i; j++ { | ||
if prices[i]-prices[j] > res { | ||
res = prices[i] - prices[j] | ||
} | ||
} | ||
} | ||
return res | ||
} |
39 changes: 39 additions & 0 deletions
src/0121_best_time_to_buy_and_sell_stock/maxprofit_test.go
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package maxprofit | ||
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import "testing" | ||
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func TestMaxProfit(t *testing.T) { | ||
testCases := [][]int{ | ||
{7, 1, 5, 3, 6, 4}, | ||
{5, 3, 2, 2, 5, 7, 9, 4}, | ||
{}, | ||
{3}, | ||
{5, 3, 2, 2, 5, 7, 9, 4,5, 3, 2, 2, 5, 7, 9, 4}, | ||
{2,4,1,11,7}, | ||
} | ||
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expected := []int{5, 7, 0, 0,7,10} | ||
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for index, data := range testCases { | ||
if res := maxProfit(data); res != expected[index] { | ||
t.Errorf("expected %d, got %d", expected[index], res) | ||
} | ||
} | ||
} | ||
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func TestMaxProfit1(t *testing.T) { | ||
testCases := [][]int{ | ||
{7, 1, 5, 3, 6, 4}, | ||
{5, 3, 2, 2, 5, 7, 9, 4}, | ||
{}, | ||
{3}, | ||
} | ||
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expected := []int{5, 7, 0, 0} | ||
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for index, data := range testCases { | ||
if res := maxProfit1(data); res != expected[index] { | ||
t.Errorf("expected %d, got %d", expected[index], res) | ||
} | ||
} | ||
} |
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