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feat: add cpp solution to lc problem: No.0404 #2587
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35 changes: 35 additions & 0 deletions
solution/0400-0499/0404.Sum of Left Leaves/Solution2.cpp
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,35 @@ | ||
| /** | ||
| * Definition for a binary tree node. | ||
| * struct TreeNode { | ||
| * int val; | ||
| * TreeNode *left; | ||
| * TreeNode *right; | ||
| * TreeNode() : val(0), left(nullptr), right(nullptr) {} | ||
| * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} | ||
| * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} | ||
| * }; | ||
| */ | ||
| class Solution { | ||
| public: | ||
| int sumOfLeftLeaves(TreeNode* root) { | ||
| if (!root) { | ||
| return 0; | ||
| } | ||
| int ans = 0; | ||
| stack<TreeNode*> stk{{root}}; | ||
| while (!stk.empty()) { | ||
| root = stk.top(), stk.pop(); | ||
| if (root->left) { | ||
| if (!root->left->left && !root->left->right) { | ||
| ans += root->left->val; | ||
| } else { | ||
| stk.push(root->left); | ||
| } | ||
| } | ||
| if (root->right) { | ||
| stk.push(root->right); | ||
| } | ||
| } | ||
| return ans; | ||
| } | ||
| }; |
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