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‎递归与回溯/LeetCode 1219. 黄金矿工.md

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这题也是搜索相关,四个方向,不允许重复,不过这次我们需要从不同起点搜索,而且为了减少搜索次数,我们得从黄金数量不为0的点开始搜。然后每当走不下去的时候,就比较一下当前黄金数量,求出最大值即可。
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![](https://img-blog.csdnimg.cn/20200913111143927.png?x-oss-process=image/watermark,type_ZmFuZ3poZW5naGVpdGk,shadow_10,text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80MjQyOTcxOA==,size_16,color_FFFFFF,t_70#pic_center)
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```javascript
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/**
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* @param {number[][]} grid

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AltStyle によって変換されたページ (->オリジナル) /