Skip to content

Navigation Menu

Sign in
Appearance settings

Search code, repositories, users, issues, pull requests...

Provide feedback

We read every piece of feedback, and take your input very seriously.

Saved searches

Use saved searches to filter your results more quickly

Sign up
Appearance settings

[pull] master from youngyangyang04:master #373

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
pull merged 6 commits into AlgorithmAndLeetCode:master from youngyangyang04:master
Nov 6, 2023
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
24 changes: 13 additions & 11 deletions problems/0053.最大子序和(动态规划).md
View file Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -226,18 +226,20 @@ object Solution {

```typescript
function maxSubArray(nums: number[]): number {
/**
dp[i]:以nums[i]结尾的最大和
*/
const dp: number[] = []
dp[0] = nums[0];
let resMax: number = 0;
for (let i = 1; i < nums.length; i++) {
dp[i] = Math.max(dp[i - 1] + nums[i], nums[i]);
resMax = Math.max(resMax, dp[i]);
const len = nums.length
if (len === 1) return nums[0]

const dp: number[] = new Array(len)
let resMax: number = dp[0] = nums[0]

for (let i = 1; i < len; i++) {
dp[i] = Math.max(dp[i - 1] + nums[i], nums[i])
// 注意值为负数的情况
if (dp[i] > resMax) resMax = dp[i]
}
return resMax;
};

return resMax
}
```


Expand Down
47 changes: 36 additions & 11 deletions problems/0392.判断子序列.md
View file Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -216,26 +216,51 @@ const isSubsequence = (s, t) => {

### TypeScript:

> 二维数组

```typescript
function isSubsequence(s: string, t: string): boolean {
/**
dp[i][j]: s的前i-1个,t的前j-1个,最长公共子序列的长度
*/
const sLen: number = s.length,
tLen: number = t.length;
const dp: number[][] = new Array(sLen + 1).fill(0)
.map(_ => new Array(tLen + 1).fill(0));
const sLen= s.length
const tLen= t.length
const dp: number[][] = new Array(sLen + 1).fill(0).map(_ => new Array(tLen + 1).fill(0))

for (let i = 1; i <= sLen; i++) {
for (let j = 1; j <= tLen; j++) {
if (s[i - 1] === t[j - 1]) {
dp[i][j] = dp[i - 1][j - 1] + 1;
} else {
dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]);
}
if (s[i - 1] === t[j - 1]) dp[i][j] = dp[i - 1][j - 1] + 1
// 只需要取 j-2 的 dp 值即可,不用考虑 i-2
else dp[i][j] = dp[i][j - 1]
}
}
return dp[sLen][tLen] === s.length;
};
return dp[sLen][tLen] === s.length
}
```

> 滚动数组
```typescript
function isSubsequence(s: string, t: string): boolean {
const sLen = s.length
const tLen = t.length
const dp: number[] = new Array(tLen + 1).fill(0)

for (let i = 1; i <= sLen; i++) {
let prev: number = 0;
let temp: number = 0;
for (let j = 1; j <= tLen; j++) {
// 备份一下当前状态(经过上层迭代后的)
temp = dp[j]
// prev 相当于 dp[j-1](累加了上层的状态)
// 如果单纯 dp[j-1] 则不会包含上层状态
if (s[i - 1] === t[j - 1]) dp[j] = prev + 1
else dp[j] = dp[j - 1]
// 继续使用上一层状态更新参数用于当前层下一个状态
prev = temp
}
}
return dp[tLen] === sLen
}
```

### Go:
Expand Down
30 changes: 30 additions & 0 deletions problems/1035.不相交的线.md
View file Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -221,6 +221,8 @@ const maxUncrossedLines = (nums1, nums2) => {

### TypeScript:

> 二维数组

```typescript
function maxUncrossedLines(nums1: number[], nums2: number[]): number {
/**
Expand All @@ -243,6 +245,34 @@ function maxUncrossedLines(nums1: number[], nums2: number[]): number {
};
```

> 滚动数组
```typescript
function maxUncrossedLines(nums1: number[], nums2: number[]): number {
const len1 = nums1.length
const len2 = nums2.length

const dp: number[] = new Array(len2 + 1).fill(0)

for (let i = 1; i <= len1; i++) {
let prev: number = 0;
let temp: number = 0;
for (let j = 1; j <= len2; j++) {
// 备份一下当前状态(经过上层迭代后的)
temp = dp[j]
// prev 相当于 dp[j-1](累加了上层的状态)
// 如果单纯 dp[j-1] 则不会包含上层状态
if (nums1[i - 1] === nums2[j - 1]) dp[j] = prev + 1
// dp[j] 表示之前的 dp[i][j-1],dp[j-1] 表示 dp[i-1][j]
else dp[j] = Math.max(dp[j], dp[j - 1])
// 继续使用上一层状态更新参数用于当前层下一个状态
prev = temp
}
}
return dp[len2]
}
```


<p align="center">
<a href="https://programmercarl.com/other/kstar.html" target="_blank">
<img src="../pics/网站星球宣传海报.jpg" width="1000"/>
Expand Down

AltStyle によって変換されたページ (->オリジナル) /