Skip to content

Navigation Menu

Sign in
Appearance settings

Search code, repositories, users, issues, pull requests...

Provide feedback

We read every piece of feedback, and take your input very seriously.

Saved searches

Use saved searches to filter your results more quickly

Sign up
Appearance settings

[pull] master from youngyangyang04:master #358

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
pull merged 3 commits into AlgorithmAndLeetCode:master from youngyangyang04:master
Oct 5, 2023
Merged
Changes from 1 commit
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
Next Next commit
feat(0213 打家劫舍II): 使Go版本更符合Go习惯
  • Loading branch information
aFlyBird0 committed Sep 28, 2023
commit 5117a288422612c5e4a845d7ecdecff8448334d0
44 changes: 25 additions & 19 deletions problems/0213.打家劫舍II.md
View file Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -225,32 +225,38 @@ class Solution:
// 打家劫舍II 动态规划
// 时间复杂度O(n) 空间复杂度O(n)
func rob(nums []int) int {
if len(nums) == 1 {
return nums[0]
// 如果长度为0或1,那么有没有环的限制都一样
if len(nums) <= 1 {
return robWithoutCircle(nums)
}
if len(nums) == 2 {
return max(nums[0], nums[1])
}

result1 := robRange(nums, 0)
result2 := robRange(nums, 1)
return max(result1, result2)

// 否则,去头或去尾,取最大
res1 := robWithoutCircle(nums[:len(nums)-1])
res2 := robWithoutCircle(nums[1:])

return max(res1, res2)
}

// 偷盗指定的范围
func robRange(nums []int, start int) int {
// 原始的打家劫舍版
func robWithoutCircle(nums []int) int {
switch len(nums) {
case 0: return 0
case 1: return nums[0]
}
dp := make([]int, len(nums))
dp[1] = nums[start]

for i := 2; i < len(nums); i++ {
dp[i] = max(dp[i - 2] + nums[i - 1 + start], dp[i - 1])
dp[0]=nums[0]
dp[1] = max(nums[0], nums[1])

for i:=2; i<len(nums); i++ {
dp[i] = max(dp[i-1], dp[i-2]+nums[i])
}

return dp[len(nums) - 1]

return dp[len(nums)-1]

}

func max(a, b int) int {
if a > b {
func max(a, b int) int {
if a>b {
return a
}
return b
Expand Down

AltStyle によって変換されたページ (->オリジナル) /