Skip to content

Navigation Menu

Sign in
Appearance settings

Search code, repositories, users, issues, pull requests...

Provide feedback

We read every piece of feedback, and take your input very seriously.

Saved searches

Use saved searches to filter your results more quickly

Sign up
Appearance settings

[pull] master from wisdompeak:master #5

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
pull merged 5 commits into AlgorithmAndLeetCode:master from wisdompeak:master
Jun 2, 2022
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
Original file line number Diff line number Diff line change
@@ -0,0 +1,88 @@
class Solution {
vector<pair<int,int>>dir = {{1,0},{-1,0},{0,1},{0,-1}};
public:
int minimumObstacles(vector<vector<int>>& grid)
{
int m = grid.size();
int n = grid[0].size();
if (m==1 && n==1) return 0;
vector<vector<int>>visited(m, vector<int>(n,0));

queue<pair<int,int>>q;
q.push({0,0});
visited[0][0] = 1;

int step = 0;
while (!q.empty())
{
int len = q.size();
while (len--)
{
auto [x, y] = q.front();
q.pop();

for (auto [dx, dy]: dir)
{
int i = x+dx;
int j = y+dy;

if (i<0||i>=m||j<0||j>=n) continue;
if (visited[i][j]==1) continue;
if (grid[i][j] == 1)
{
visited[i][j] = 1;
q.push({i,j});
}
else
{
for (auto [ii, jj]: travel(grid, visited, i, j))
{
if (ii==m-1 && jj==n-1)
return step;
q.push({ii,jj});
}
}
}
}
step++;
}
return 0;
}

vector<pair<int,int>>travel(vector<vector<int>>& grid, vector<vector<int>>& visited, int x0, int y0)
{
int m = grid.size();
int n = grid[0].size();

if (x0==m-1 && y0==n-1)
return {{x0, y0}};

queue<pair<int,int>>q;
q.push({x0,y0});
visited[x0][y0] = 1;

vector<pair<int,int>>rets;
while (!q.empty())
{
auto [x, y] = q.front();
q.pop();

for (auto [dx, dy] : dir)
{
int i = x+dx;
int j = y+dy;
if (i<0||i>=m||j<0||j>=n) continue;
if (visited[i][j]==1) continue;
visited[i][j] = 1;
if (i==m-1 && j==n-1)
rets.push_back({i,j});
else if (grid[i][j]==1)
rets.push_back({i,j});
else
q.push({i,j});
}
}

return rets;
}
};
5 changes: 5 additions & 0 deletions BFS/2290.Minimum-Obstacle-Removal-to-Reach-Corner/Readme.md
View file Open in desktop
Original file line number Diff line number Diff line change
@@ -0,0 +1,5 @@
### 2290.Minimum-Obstacle-Removal-to-Reach-Corner

本题的本质就是从起点到终点,采用层级BFS,最少需要穿越几个回合的障碍。而障碍与障碍之间的空气,可以忽略不计。也就是说,某个障碍与空气相邻的话,下一个回合可以通过空气到达其他的障碍。

在实现过程中,除了常规的层级BFS之外,我们还需要有一个travelAir的函数。travelAir以某个空格子为起点,遍历所有能"隔空"访问的障碍物。这些障碍物需要加入下一回合BFS的队列中去。
38 changes: 38 additions & 0 deletions DFS/473.Matchsticks-to-Square/473.Matchsticks-to-Square_v2.cpp
View file Open in desktop
Original file line number Diff line number Diff line change
@@ -0,0 +1,38 @@
class Solution {
bool divide2(vector<int>& sticks, int target) {
int n = sticks.size();
for(int state = 0; state < (1<<n); ++state) {
int cur = 0;
for(int i = 0; i < n; ++i) {
if((state>>i)&1) cur += sticks[i];
}
if(cur == target) return true;
}
return false;
}
public:
bool makesquare(vector<int>& matchsticks) {
int total = accumulate(matchsticks.begin(), matchsticks.end(), 0);
if(total % 4 != 0) return false;

int n = matchsticks.size();

for(int state = 0; state < (1<<n); ++state) {
int cur = 0;
for(int i = 0; i < n; ++i) {
if((state>>i)&1) cur += matchsticks[i];
}
if(cur == total / 2) {
vector<int> v1, v2;
for(int i = 0; i < n; ++i) {
if((state>>i)&1) v1.push_back(matchsticks[i]);
else v2.push_back(matchsticks[i]);
}

if(divide2(v1, total / 4) && divide2(v2, total / 4)) return true;
}
}

return false;
}
};
1 change: 1 addition & 0 deletions Readme.md
View file Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -487,6 +487,7 @@
[2045.Second-Minimum-Time-to-Reach-Destination](https://github.com/wisdompeak/LeetCode/tree/master/BFS/2045.Second-Minimum-Time-to-Reach-Destination) (M+)
[2101.Detonate-the-Maximum-Bombs](https://github.com/wisdompeak/LeetCode/tree/master/BFS/2101.Detonate-the-Maximum-Bombs) (M+)
[2258.Escape-the-Spreading-Fire](https://github.com/wisdompeak/LeetCode/tree/master/BFS/2258.Escape-the-Spreading-Fire) (H+)
[2290.Minimum-Obstacle-Removal-to-Reach-Corner](https://github.com/wisdompeak/LeetCode/tree/master/BFS/2290.Minimum-Obstacle-Removal-to-Reach-Corner) (M+)
* ``Multi State``
[847.Shortest-Path-Visiting-All-Nodes](https://github.com/wisdompeak/LeetCode/tree/master/BFS/847.Shortest-Path-Visiting-All-Nodes) (H-)
[864.Shortest-Path-to-Get-All-Keys](https://github.com/wisdompeak/LeetCode/tree/master/BFS/864.Shortest-Path-to-Get-All-Keys) (H-)
Expand Down

AltStyle によって変換されたページ (->オリジナル) /