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[pull] main from itcharge:main #190

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Merged
pull merged 2 commits into AlgorithmAndLeetCode:main from itcharge:main
Jul 4, 2024
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Expand Up @@ -83,7 +83,7 @@

- 如果 $nums[j] < nums[i],ドル则 $nums[i]$ 可以接在 $nums[j]$ 后面,此时以 $nums[i]$ 结尾的最长递增子序列长度会在「以 $nums[j]$ 结尾的最长递增子序列长度」的基础上加 1ドル,ドル即:$dp[i] = dp[j] + 1$。

- 如果 $nums[j] \le nums[i],ドル则 $nums[i]$ 不可以接在 $nums[j]$ 后面,可以直接跳过。
- 如果 $nums[j] \ge nums[i],ドル则 $nums[i]$ 不可以接在 $nums[j]$ 后面,可以直接跳过。

综上,我们的状态转移方程为:$dp[i] = max(dp[i], dp[j] + 1), 0 \le j < i, nums[j] < nums[i]$。

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AltStyle によって変換されたページ (->オリジナル) /