# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9.
# The sum of these multiples is 23.
# Find the sum of all the multiples of 3 or 5 below 1000.

class Multiples(object):
 def Multiples_three_and_five(self, num):
 num_list = []
 for i in range(1, num):
 if i % 3 == 0:
 num_list.append(i)
 elif i % 5 == 0:
 num_list.append(i)
 return num_list

 def Sum_list(self, Num_list):
 sum = 0
 for i in Num_list:
 sum = i + sum
 print 'sum of the list is %d' % (sum)
 return sum

 def Multiple_list(self, Num_list):
 result = 1
 for i in Num_list:
 result = i * result
 print 'multiple of the list is %d' % result
 return result


# refactor code 2016年6月21日
class Multiples_refactor(object):
 def Multiples_three_and_five(self, num):
 return [x for x in range(1, num) if x % 3 == 0 or x % 5 == 0]

 def Sum_list(self, Num_list):
 return sum(Num_list)

 def Multiple_list(self, Num_list):
 return reduce(lambda x, y: x * y, Num_list)


if __name__ == '__main__':
 num = 100
 Myobject = Multiples()
 Num_list = Myobject.Multiples_three_and_five(num)
 print Num_list
 print Myobject.Sum_list(Num_list)

 print "split line, refactor"
 num = 100
 Myobject = Multiples_refactor()
 Num_list = Myobject.Multiples_three_and_five(num)
 print Num_list
 print Myobject.Sum_list(Num_list)