package Maths;/*** @file** @brief Calculates the [Cross Product](https://en.wikipedia.org/wiki/Cross_product) and the magnitude of two mathematical 3D vectors.*** @details Cross Product of two vectors gives a vector.* Direction Ratios of a vector are the numeric parts of the given vector. They are the tree parts of the* vector which determine the magnitude (value) of the vector.* The method of finding a cross product is the same as finding the determinant of an order 3 matrix consisting* of the first row with unit vectors of magnitude 1, the second row with the direction ratios of the* first vector and the third row with the direction ratios of the second vector.* The magnitude of a vector is it's value expressed as a number.* Let the direction ratios of the first vector, P be: a, b, c* Let the direction ratios of the second vector, Q be: x, y, z* Therefore the calculation for the cross product can be arranged as:** ```* P x Q:* 1 1 1* a b c* x y z* ```** The direction ratios (DR) are calculated as follows:* 1st DR, J: (b * z) - (c * y)* 2nd DR, A: -((a * z) - (c * x))* 3rd DR, N: (a * y) - (b * x)** Therefore, the direction ratios of the cross product are: J, A, N* The following Java Program calculates the direction ratios of the cross products of two vector.* The program uses a function, cross() for doing so.* The direction ratios for the first and the second vector has to be passed one by one seperated by a space character.** Magnitude of a vector is the square root of the sum of the squares of the direction ratios.*** For maintaining filename consistency, Vector class has been termed as VectorCrossProduct** @author [Syed](https://github.com/roeticvampire)*/public class VectorCrossProduct {int x;int y;int z;//Default constructor, initialises all three Direction Ratios to 0VectorCrossProduct(){x=0;y=0;z=0;}/*** constructor, initialises Vector with given Direction Ratios* @param _x set to x* @param _y set to y* @param _z set to z*/VectorCrossProduct(int _x,int _y, int _z){x=_x;y=_y;z=_z;}/*** Returns the magnitude of the vector* @return double*/double magnitude(){return Math.sqrt(x*x +y*y +z*z);}/*** Returns the dot product of the current vector with a given vector* @param b: the second vector* @return int: the dot product*/int dotProduct(VectorCrossProduct b){return x*b.x + y*b.y +z*b.z;}/*** Returns the cross product of the current vector with a given vector* @param b: the second vector* @return vectorCrossProduct: the cross product*/VectorCrossProduct crossProduct(VectorCrossProduct b){VectorCrossProduct product=new VectorCrossProduct();product.x = (y * b.z) - (z * b.y);product.y = -((x * b.z) - (z * b.x));product.z = (x * b.y) - (y * b.x);return product;}/*** Display the Vector*/void displayVector(){System.out.println("x : "+x+"\ty : "+y+"\tz : "+z);}public static void main(String[] args) {test();}static void test(){//Create two vectorsVectorCrossProduct A=new VectorCrossProduct(1,-2,3);VectorCrossProduct B=new VectorCrossProduct(2,0,3);//Determine cross productVectorCrossProduct crossProd=A.crossProduct(B);crossProd.displayVector();//Determine dot productint dotProd=A.dotProduct(B);System.out.println("Dot Product of A and B: "+dotProd);}}
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