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/* -*- Mode: C; c-file-style: "python" -*- */#include <Python.h>#include <locale.h>/* Case-insensitive string match used for nan and inf detection; t should belower-case. Returns 1 for a successful match, 0 otherwise. */static intcase_insensitive_match(const char *s, const char *t){while(*t && Py_TOLOWER(*s) == *t) {s++;t++;}return *t ? 0 : 1;}/* _Py_parse_inf_or_nan: Attempt to parse a string of the form "nan", "inf" or"infinity", with an optional leading sign of "+" or "-". On success,return the NaN or Infinity as a double and set *endptr to point just beyondthe successfully parsed portion of the string. On failure, return -1.0 andset *endptr to point to the start of the string. */#ifndef PY_NO_SHORT_FLOAT_REPRdouble_Py_parse_inf_or_nan(const char *p, char **endptr){double retval;const char *s;int negate = 0;s = p;if (*s == '-') {negate = 1;s++;}else if (*s == '+') {s++;}if (case_insensitive_match(s, "inf")) {s += 3;if (case_insensitive_match(s, "inity"))s += 5;retval = _Py_dg_infinity(negate);}else if (case_insensitive_match(s, "nan")) {s += 3;retval = _Py_dg_stdnan(negate);}else {s = p;retval = -1.0;}*endptr = (char *)s;return retval;}#elsedouble_Py_parse_inf_or_nan(const char *p, char **endptr){double retval;const char *s;int negate = 0;s = p;if (*s == '-') {negate = 1;s++;}else if (*s == '+') {s++;}if (case_insensitive_match(s, "inf")) {s += 3;if (case_insensitive_match(s, "inity"))s += 5;retval = negate ? -Py_HUGE_VAL : Py_HUGE_VAL;}#ifdef Py_NANelse if (case_insensitive_match(s, "nan")) {s += 3;retval = negate ? -Py_NAN : Py_NAN;}#endifelse {s = p;retval = -1.0;}*endptr = (char *)s;return retval;}#endif/*** _PyOS_ascii_strtod:* @nptr: the string to convert to a numeric value.* @endptr: if non-%NULL, it returns the character after* the last character used in the conversion.** Converts a string to a #gdouble value.* This function behaves like the standard strtod() function* does in the C locale. It does this without actually* changing the current locale, since that would not be* thread-safe.** This function is typically used when reading configuration* files or other non-user input that should be locale independent.* To handle input from the user you should normally use the* locale-sensitive system strtod() function.** If the correct value would cause overflow, plus or minus %HUGE_VAL* is returned (according to the sign of the value), and %ERANGE is* stored in %errno. If the correct value would cause underflow,* zero is returned and %ERANGE is stored in %errno.* If memory allocation fails, %ENOMEM is stored in %errno.** This function resets %errno before calling strtod() so that* you can reliably detect overflow and underflow.** Return value: the #gdouble value.**/#ifndef PY_NO_SHORT_FLOAT_REPRstatic double_PyOS_ascii_strtod(const char *nptr, char **endptr){double result;_Py_SET_53BIT_PRECISION_HEADER;assert(nptr != NULL);/* Set errno to zero, so that we can distinguish zero resultsand underflows */errno = 0;_Py_SET_53BIT_PRECISION_START;result = _Py_dg_strtod(nptr, endptr);_Py_SET_53BIT_PRECISION_END;if (*endptr == nptr)/* string might represent an inf or nan */result = _Py_parse_inf_or_nan(nptr, endptr);return result;}#else/*Use system strtod; since strtod is locale aware, we mayhave to first fix the decimal separator.Note that unlike _Py_dg_strtod, the system strtod may not always givecorrectly rounded results.*/static double_PyOS_ascii_strtod(const char *nptr, char **endptr){char *fail_pos;double val;struct lconv *locale_data;const char *decimal_point;size_t decimal_point_len;const char *p, *decimal_point_pos;const char *end = NULL; /* Silence gcc */const char *digits_pos = NULL;int negate = 0;assert(nptr != NULL);fail_pos = NULL;locale_data = localeconv();decimal_point = locale_data->decimal_point;decimal_point_len = strlen(decimal_point);assert(decimal_point_len != 0);decimal_point_pos = NULL;/* Parse infinities and nans */val = _Py_parse_inf_or_nan(nptr, endptr);if (*endptr != nptr)return val;/* Set errno to zero, so that we can distinguish zero resultsand underflows */errno = 0;/* We process the optional sign manually, then pass the remainder tothe system strtod. This ensures that the result of an underflowhas the correct sign. (bug #1725) */p = nptr;/* Process leading sign, if present */if (*p == '-') {negate = 1;p++;}else if (*p == '+') {p++;}/* Some platform strtods accept hex floats; Python shouldn't (at themoment), so we check explicitly for strings starting with '0x'. */if (*p == '0' && (*(p+1) == 'x' || *(p+1) == 'X'))goto invalid_string;/* Check that what's left begins with a digit or decimal point */if (!Py_ISDIGIT(*p) && *p != '.')goto invalid_string;digits_pos = p;if (decimal_point[0] != '.' ||decimal_point[1] != 0){/* Look for a '.' in the input; if present, it'll need to beswapped for the current locale's decimal point before wecall strtod. On the other hand, if we find the currentlocale's decimal point then the input is invalid. */while (Py_ISDIGIT(*p))p++;if (*p == '.'){decimal_point_pos = p++;/* locate end of number */while (Py_ISDIGIT(*p))p++;if (*p == 'e' || *p == 'E')p++;if (*p == '+' || *p == '-')p++;while (Py_ISDIGIT(*p))p++;end = p;}else if (strncmp(p, decimal_point, decimal_point_len) == 0)/* Python bug #1417699 */goto invalid_string;/* For the other cases, we need not convert the decimalpoint */}if (decimal_point_pos) {char *copy, *c;/* Create a copy of the input, with the '.' converted to thelocale-specific decimal point */copy = (char *)PyMem_MALLOC(end - digits_pos +1 + decimal_point_len);if (copy == NULL) {*endptr = (char *)nptr;errno = ENOMEM;return val;}c = copy;memcpy(c, digits_pos, decimal_point_pos - digits_pos);c += decimal_point_pos - digits_pos;memcpy(c, decimal_point, decimal_point_len);c += decimal_point_len;memcpy(c, decimal_point_pos + 1,end - (decimal_point_pos + 1));c += end - (decimal_point_pos + 1);*c = 0;val = strtod(copy, &fail_pos);if (fail_pos){if (fail_pos > decimal_point_pos)fail_pos = (char *)digits_pos +(fail_pos - copy) -(decimal_point_len - 1);elsefail_pos = (char *)digits_pos +(fail_pos - copy);}PyMem_FREE(copy);}else {val = strtod(digits_pos, &fail_pos);}if (fail_pos == digits_pos)goto invalid_string;if (negate && fail_pos != nptr)val = -val;*endptr = fail_pos;return val;invalid_string:*endptr = (char*)nptr;errno = EINVAL;return -1.0;}#endif/* PyOS_string_to_double converts a null-terminated byte string s (interpretedas a string of ASCII characters) to a float. The string should not haveleading or trailing whitespace. The conversion is independent of thecurrent locale.If endptr is NULL, try to convert the whole string. Raise ValueError andreturn -1.0 if the string is not a valid representation of a floating-pointnumber.If endptr is non-NULL, try to convert as much of the string as possible.If no initial segment of the string is the valid representation of afloating-point number then *endptr is set to point to the beginning of thestring, -1.0 is returned and again ValueError is raised.On overflow (e.g., when trying to convert '1e500' on an IEEE 754 machine),if overflow_exception is NULL then +-Py_HUGE_VAL is returned, and no Pythonexception is raised. Otherwise, overflow_exception should point toa Python exception, this exception will be raised, -1.0 will be returned,and *endptr will point just past the end of the converted value.If any other failure occurs (for example lack of memory), -1.0 is returnedand the appropriate Python exception will have been set.*/doublePyOS_string_to_double(const char *s,char **endptr,PyObject *overflow_exception){double x, result=-1.0;char *fail_pos;errno = 0;PyFPE_START_PROTECT("PyOS_string_to_double", return -1.0)x = _PyOS_ascii_strtod(s, &fail_pos);PyFPE_END_PROTECT(x)if (errno == ENOMEM) {PyErr_NoMemory();fail_pos = (char *)s;}else if (!endptr && (fail_pos == s || *fail_pos != '0円'))PyErr_Format(PyExc_ValueError,"could not convert string to float: ""'%.200s'", s);else if (fail_pos == s)PyErr_Format(PyExc_ValueError,"could not convert string to float: ""'%.200s'", s);else if (errno == ERANGE && fabs(x) >= 1.0 && overflow_exception)PyErr_Format(overflow_exception,"value too large to convert to float: ""'%.200s'", s);elseresult = x;if (endptr != NULL)*endptr = fail_pos;return result;}/* Remove underscores that follow the underscore placement rule fromthe string and then call the `innerfunc` function on the result.It should return a new object or NULL on exception.`what` is used for the error message emitted when underscores are detectedthat don't follow the rule. `arg` is an opaque pointer passed to the innerfunction.This is used to implement underscore-agnostic conversion for floatsand complex numbers.*/PyObject *_Py_string_to_number_with_underscores(const char *s, Py_ssize_t orig_len, const char *what, PyObject *obj, void *arg,PyObject *(*innerfunc)(const char *, Py_ssize_t, void *)){char prev;const char *p, *last;char *dup, *end;PyObject *result;assert(s[orig_len] == '0円');if (strchr(s, '_') == NULL) {return innerfunc(s, orig_len, arg);}dup = PyMem_Malloc(orig_len + 1);if (dup == NULL) {return PyErr_NoMemory();}end = dup;prev = '0円';last = s + orig_len;for (p = s; *p; p++) {if (*p == '_') {/* Underscores are only allowed after digits. */if (!(prev >= '0' && prev <= '9')) {goto error;}}else {*end++ = *p;/* Underscores are only allowed before digits. */if (prev == '_' && !(*p >= '0' && *p <= '9')) {goto error;}}prev = *p;}/* Underscores are not allowed at the end. */if (prev == '_') {goto error;}/* No embedded NULs allowed. */if (p != last) {goto error;}*end = '0円';result = innerfunc(dup, end - dup, arg);PyMem_Free(dup);return result;error:PyMem_Free(dup);PyErr_Format(PyExc_ValueError,"could not convert string to %s: ""%R", what, obj);return NULL;}#ifdef PY_NO_SHORT_FLOAT_REPR/* Given a string that may have a decimal point in the currentlocale, change it back to a dot. Since the string cannot getlonger, no need for a maximum buffer size parameter. */Py_LOCAL_INLINE(void)change_decimal_from_locale_to_dot(char* buffer){struct lconv *locale_data = localeconv();const char *decimal_point = locale_data->decimal_point;if (decimal_point[0] != '.' || decimal_point[1] != 0) {size_t decimal_point_len = strlen(decimal_point);if (*buffer == '+' || *buffer == '-')buffer++;while (Py_ISDIGIT(*buffer))buffer++;if (strncmp(buffer, decimal_point, decimal_point_len) == 0) {*buffer = '.';buffer++;if (decimal_point_len > 1) {/* buffer needs to get smaller */size_t rest_len = strlen(buffer +(decimal_point_len - 1));memmove(buffer,buffer + (decimal_point_len - 1),rest_len);buffer[rest_len] = 0;}}}}/* From the C99 standard, section 7.19.6:The exponent always contains at least two digits, and only as many more digitsas necessary to represent the exponent.*/#define MIN_EXPONENT_DIGITS 2/* Ensure that any exponent, if present, is at least MIN_EXPONENT_DIGITSin length. */Py_LOCAL_INLINE(void)ensure_minimum_exponent_length(char* buffer, size_t buf_size){char *p = strpbrk(buffer, "eE");if (p && (*(p + 1) == '-' || *(p + 1) == '+')) {char *start = p + 2;int exponent_digit_cnt = 0;int leading_zero_cnt = 0;int in_leading_zeros = 1;int significant_digit_cnt;/* Skip over the exponent and the sign. */p += 2;/* Find the end of the exponent, keeping track of leadingzeros. */while (*p && Py_ISDIGIT(*p)) {if (in_leading_zeros && *p == '0')++leading_zero_cnt;if (*p != '0')in_leading_zeros = 0;++p;++exponent_digit_cnt;}significant_digit_cnt = exponent_digit_cnt - leading_zero_cnt;if (exponent_digit_cnt == MIN_EXPONENT_DIGITS) {/* If there are 2 exactly digits, we're done,regardless of what they contain */}else if (exponent_digit_cnt > MIN_EXPONENT_DIGITS) {int extra_zeros_cnt;/* There are more than 2 digits in the exponent. Seeif we can delete some of the leading zeros */if (significant_digit_cnt < MIN_EXPONENT_DIGITS)significant_digit_cnt = MIN_EXPONENT_DIGITS;extra_zeros_cnt = exponent_digit_cnt -significant_digit_cnt;/* Delete extra_zeros_cnt worth of characters from thefront of the exponent */assert(extra_zeros_cnt >= 0);/* Add one to significant_digit_cnt to copy thetrailing 0 byte, thus setting the length */memmove(start,start + extra_zeros_cnt,significant_digit_cnt + 1);}else {/* If there are fewer than 2 digits, add zerosuntil there are 2, if there's enough room */int zeros = MIN_EXPONENT_DIGITS - exponent_digit_cnt;if (start + zeros + exponent_digit_cnt + 1< buffer + buf_size) {memmove(start + zeros, start,exponent_digit_cnt + 1);memset(start, '0', zeros);}}}}/* Remove trailing zeros after the decimal point from a numeric string; alsoremove the decimal point if all digits following it are zero. The numericstring must end in '0円', and should not have any leading or trailingwhitespace. Assumes that the decimal point is '.'. */Py_LOCAL_INLINE(void)remove_trailing_zeros(char *buffer){char *old_fraction_end, *new_fraction_end, *end, *p;p = buffer;if (*p == '-' || *p == '+')/* Skip leading sign, if present */++p;while (Py_ISDIGIT(*p))++p;/* if there's no decimal point there's nothing to do */if (*p++ != '.')return;/* scan any digits after the point */while (Py_ISDIGIT(*p))++p;old_fraction_end = p;/* scan up to ending '0円' */while (*p != '0円')p++;/* +1 to make sure that we move the null byte as well */end = p+1;/* scan back from fraction_end, looking for removable zeros */p = old_fraction_end;while (*(p-1) == '0')--p;/* and remove point if we've got that far */if (*(p-1) == '.')--p;new_fraction_end = p;memmove(new_fraction_end, old_fraction_end, end-old_fraction_end);}/* Ensure that buffer has a decimal point in it. The decimal point will notbe in the current locale, it will always be '.'. Don't add a decimal pointif an exponent is present. Also, convert to exponential notation whereadding a '.0' would produce too many significant digits (see issue 5864).Returns a pointer to the fixed buffer, or NULL on failure.*/Py_LOCAL_INLINE(char *)ensure_decimal_point(char* buffer, size_t buf_size, int precision){int digit_count, insert_count = 0, convert_to_exp = 0;const char *chars_to_insert;char *digits_start;/* search for the first non-digit character */char *p = buffer;if (*p == '-' || *p == '+')/* Skip leading sign, if present. I think this could onlyever be '-', but it can't hurt to check for both. */++p;digits_start = p;while (*p && Py_ISDIGIT(*p))++p;digit_count = Py_SAFE_DOWNCAST(p - digits_start, Py_ssize_t, int);if (*p == '.') {if (Py_ISDIGIT(*(p+1))) {/* Nothing to do, we already have a decimalpoint and a digit after it */}else {/* We have a decimal point, but no followingdigit. Insert a zero after the decimal. *//* can't ever get here via PyOS_double_to_string */assert(precision == -1);++p;chars_to_insert = "0";insert_count = 1;}}else if (!(*p == 'e' || *p == 'E')) {/* Don't add ".0" if we have an exponent. */if (digit_count == precision) {/* issue 5864: don't add a trailing .0 in the casewhere the '%g'-formatted result already has as manysignificant digits as were requested. Switch toexponential notation instead. */convert_to_exp = 1;/* no exponent, no point, and we shouldn't land herefor infs and nans, so we must be at the end of thestring. */assert(*p == '0円');}else {assert(precision == -1 || digit_count < precision);chars_to_insert = ".0";insert_count = 2;}}if (insert_count) {size_t buf_len = strlen(buffer);if (buf_len + insert_count + 1 >= buf_size) {/* If there is not enough room in the bufferfor the additional text, just skip it. It'snot worth generating an error over. */}else {memmove(p + insert_count, p,buffer + strlen(buffer) - p + 1);memcpy(p, chars_to_insert, insert_count);}}if (convert_to_exp) {int written;size_t buf_avail;p = digits_start;/* insert decimal point */assert(digit_count >= 1);memmove(p+2, p+1, digit_count); /* safe, but overwrites nul */p[1] = '.';p += digit_count+1;assert(p <= buf_size+buffer);buf_avail = buf_size+buffer-p;if (buf_avail == 0)return NULL;/* Add exponent. It's okay to use lower case 'e': we onlyarrive here as a result of using the empty format code orrepr/str builtins and those never want an upper case 'E' */written = PyOS_snprintf(p, buf_avail, "e%+.02d", digit_count-1);if (!(0 <= written &&written < Py_SAFE_DOWNCAST(buf_avail, size_t, int)))/* output truncated, or something else bad happened */return NULL;remove_trailing_zeros(buffer);}return buffer;}/* see FORMATBUFLEN in unicodeobject.c */#define FLOAT_FORMATBUFLEN 120/*** _PyOS_ascii_formatd:* @buffer: A buffer to place the resulting string in* @buf_size: The length of the buffer.* @format: The printf()-style format to use for the* code to use for converting.* @d: The #gdouble to convert* @precision: The precision to use when formatting.** Converts a #gdouble to a string, using the '.' as* decimal point. To format the number you pass in* a printf()-style format string. Allowed conversion* specifiers are 'e', 'E', 'f', 'F', 'g', 'G', and 'Z'.** 'Z' is the same as 'g', except it always has a decimal and* at least one digit after the decimal.** Return value: The pointer to the buffer with the converted string.* On failure returns NULL but does not set any Python exception.**/static char *_PyOS_ascii_formatd(char *buffer,size_t buf_size,const char *format,double d,int precision){char format_char;size_t format_len = strlen(format);/* Issue 2264: code 'Z' requires copying the format. 'Z' is 'g', butalso with at least one character past the decimal. */char tmp_format[FLOAT_FORMATBUFLEN];/* The last character in the format string must be the format char */format_char = format[format_len - 1];if (format[0] != '%')return NULL;/* I'm not sure why this test is here. It's ensuring that the formatstring after the first character doesn't have a single quote, alowercase l, or a percent. This is the reverse of the commented-outtest about 10 lines ago. */if (strpbrk(format + 1, "'l%"))return NULL;/* Also curious about this function is that it accepts format stringslike "%xg", which are invalid for floats. In general, theinterface to this function is not very good, but changing it isdifficult because it's a public API. */if (!(format_char == 'e' || format_char == 'E' ||format_char == 'f' || format_char == 'F' ||format_char == 'g' || format_char == 'G' ||format_char == 'Z'))return NULL;/* Map 'Z' format_char to 'g', by copying the format string andreplacing the final char with a 'g' */if (format_char == 'Z') {if (format_len + 1 >= sizeof(tmp_format)) {/* The format won't fit in our copy. Error out. Inpractice, this will never happen and will bedetected by returning NULL */return NULL;}strcpy(tmp_format, format);tmp_format[format_len - 1] = 'g';format = tmp_format;}/* Have PyOS_snprintf do the hard work */PyOS_snprintf(buffer, buf_size, format, d);/* Do various fixups on the return string *//* Get the current locale, and find the decimal point string.Convert that string back to a dot. */change_decimal_from_locale_to_dot(buffer);/* If an exponent exists, ensure that the exponent is at leastMIN_EXPONENT_DIGITS digits, providing the buffer is large enoughfor the extra zeros. Also, if there are more thanMIN_EXPONENT_DIGITS, remove as many zeros as possible until we getback to MIN_EXPONENT_DIGITS */ensure_minimum_exponent_length(buffer, buf_size);/* If format_char is 'Z', make sure we have at least one characterafter the decimal point (and make sure we have a decimal point);also switch to exponential notation in some edge cases where theextra character would produce more significant digits that wereally want. */if (format_char == 'Z')buffer = ensure_decimal_point(buffer, buf_size, precision);return buffer;}/* The fallback code to use if _Py_dg_dtoa is not available. */char * PyOS_double_to_string(double val,char format_code,int precision,int flags,int *type){char format[32];Py_ssize_t bufsize;char *buf;int t, exp;int upper = 0;/* Validate format_code, and map upper and lower case */switch (format_code) {case 'e': /* exponent */case 'f': /* fixed */case 'g': /* general */break;case 'E':upper = 1;format_code = 'e';break;case 'F':upper = 1;format_code = 'f';break;case 'G':upper = 1;format_code = 'g';break;case 'r': /* repr format *//* Supplied precision is unused, must be 0. */if (precision != 0) {PyErr_BadInternalCall();return NULL;}/* The repr() precision (17 significant decimal digits) is theminimal number that is guaranteed to have enough precisionso that if the number is read back in the exact same binaryvalue is recreated. This is true for IEEE floating pointby design, and also happens to work for all other modernhardware. */precision = 17;format_code = 'g';break;default:PyErr_BadInternalCall();return NULL;}/* Here's a quick-and-dirty calculation to figure out how big a bufferwe need. In general, for a finite float we need:1 byte for each digit of the decimal significand, and1 for a possible sign1 for a possible decimal point2 for a possible [eE][+-]1 for each digit of the exponent; if we allow 19 digitstotal then we're safe up to exponents of 2**63.1 for the trailing nul byteThis gives a total of 24 + the number of digits in the significand,and the number of digits in the significand is:for 'g' format: at most precision, except possiblywhen precision == 0, when it's 1.for 'e' format: precision+1for 'f' format: precision digits after the point, at least 1before. To figure out how many digits appear before the pointwe have to examine the size of the number. If fabs(val) < 1.0then there will be only one digit before the point. Iffabs(val) >= 1.0, then there are at most1+floor(log10(ceiling(fabs(val))))digits before the point (where the 'ceiling' allows for thepossibility that the rounding rounds the integer part of valup). A safe upper bound for the above quantity is1+floor(exp/3), where exp is the unique integer such that 0.5<= fabs(val)/2**exp < 1.0. This exp can be obtained fromfrexp.So we allow room for precision+1 digits for all formats, plus anextra floor(exp/3) digits for 'f' format.*/if (Py_IS_NAN(val) || Py_IS_INFINITY(val))/* 3 for 'inf'/'nan', 1 for sign, 1 for '0円' */bufsize = 5;else {bufsize = 25 + precision;if (format_code == 'f' && fabs(val) >= 1.0) {frexp(val, &exp);bufsize += exp/3;}}buf = PyMem_Malloc(bufsize);if (buf == NULL) {PyErr_NoMemory();return NULL;}/* Handle nan and inf. */if (Py_IS_NAN(val)) {strcpy(buf, "nan");t = Py_DTST_NAN;} else if (Py_IS_INFINITY(val)) {if (copysign(1., val) == 1.)strcpy(buf, "inf");elsestrcpy(buf, "-inf");t = Py_DTST_INFINITE;} else {t = Py_DTST_FINITE;if (flags & Py_DTSF_ADD_DOT_0)format_code = 'Z';PyOS_snprintf(format, sizeof(format), "%%%s.%i%c",(flags & Py_DTSF_ALT ? "#" : ""), precision,format_code);_PyOS_ascii_formatd(buf, bufsize, format, val, precision);}/* Add sign when requested. It's convenient (esp. when formattingcomplex numbers) to include a sign even for inf and nan. */if (flags & Py_DTSF_SIGN && buf[0] != '-') {size_t len = strlen(buf);/* the bufsize calculations above should ensure that we've gotspace to add a sign */assert((size_t)bufsize >= len+2);memmove(buf+1, buf, len+1);buf[0] = '+';}if (upper) {/* Convert to upper case. */char *p1;for (p1 = buf; *p1; p1++)*p1 = Py_TOUPPER(*p1);}if (type)*type = t;return buf;}#else/* _Py_dg_dtoa is available. *//* I'm using a lookup table here so that I don't have to invent a non-localespecific way to convert to uppercase */#define OFS_INF 0#define OFS_NAN 1#define OFS_E 2/* The lengths of these are known to the code below, so don't change them */static const char * const lc_float_strings[] = {"inf","nan","e",};static const char * const uc_float_strings[] = {"INF","NAN","E",};/* Convert a double d to a string, and return a PyMem_Malloc'd block ofmemory contain the resulting string.Arguments:d is the double to be convertedformat_code is one of 'e', 'f', 'g', 'r'. 'e', 'f' and 'g'correspond to '%e', '%f' and '%g'; 'r' corresponds to repr.mode is one of '0', '2' or '3', and is completely determined byformat_code: 'e' and 'g' use mode 2; 'f' mode 3, 'r' mode 0.precision is the desired precisionalways_add_sign is nonzero if a '+' sign should be included for positivenumbersadd_dot_0_if_integer is nonzero if integers in non-exponential formshould have ".0" added. Only applies to format codes 'r' and 'g'.use_alt_formatting is nonzero if alternative formatting should beused. Only applies to format codes 'e', 'f' and 'g'. For code 'g',at most one of use_alt_formatting and add_dot_0_if_integer shouldbe nonzero.type, if non-NULL, will be set to one of these constants to identifythe type of the 'd' argument:Py_DTST_FINITEPy_DTST_INFINITEPy_DTST_NANReturns a PyMem_Malloc'd block of memory containing the resulting string,or NULL on error. If NULL is returned, the Python error has been set.*/static char *format_float_short(double d, char format_code,int mode, int precision,int always_add_sign, int add_dot_0_if_integer,int use_alt_formatting, const char * const *float_strings,int *type){char *buf = NULL;char *p = NULL;Py_ssize_t bufsize = 0;char *digits, *digits_end;int decpt_as_int, sign, exp_len, exp = 0, use_exp = 0;Py_ssize_t decpt, digits_len, vdigits_start, vdigits_end;_Py_SET_53BIT_PRECISION_HEADER;/* _Py_dg_dtoa returns a digit string (no decimal point or exponent).Must be matched by a call to _Py_dg_freedtoa. */_Py_SET_53BIT_PRECISION_START;digits = _Py_dg_dtoa(d, mode, precision, &decpt_as_int, &sign,&digits_end);_Py_SET_53BIT_PRECISION_END;decpt = (Py_ssize_t)decpt_as_int;if (digits == NULL) {/* The only failure mode is no memory. */PyErr_NoMemory();goto exit;}assert(digits_end != NULL && digits_end >= digits);digits_len = digits_end - digits;if (digits_len && !Py_ISDIGIT(digits[0])) {/* Infinities and nans here; adapt Gay's output,so convert Infinity to inf and NaN to nan, andignore sign of nan. Then return. *//* ignore the actual sign of a nan */if (digits[0] == 'n' || digits[0] == 'N')sign = 0;/* We only need 5 bytes to hold the result "+inf0円" . */bufsize = 5; /* Used later in an assert. */buf = (char *)PyMem_Malloc(bufsize);if (buf == NULL) {PyErr_NoMemory();goto exit;}p = buf;if (sign == 1) {*p++ = '-';}else if (always_add_sign) {*p++ = '+';}if (digits[0] == 'i' || digits[0] == 'I') {strncpy(p, float_strings[OFS_INF], 3);p += 3;if (type)*type = Py_DTST_INFINITE;}else if (digits[0] == 'n' || digits[0] == 'N') {strncpy(p, float_strings[OFS_NAN], 3);p += 3;if (type)*type = Py_DTST_NAN;}else {/* shouldn't get here: Gay's code should always returnsomething starting with a digit, an 'I', or 'N' */Py_UNREACHABLE();}goto exit;}/* The result must be finite (not inf or nan). */if (type)*type = Py_DTST_FINITE;/* We got digits back, format them. We may need to pad 'digits'either on the left or right (or both) with extra zeros, so ingeneral the resulting string has the form[<sign>]<zeros><digits><zeros>[<exponent>]where either of the <zeros> pieces could be empty, and there's adecimal point that could appear either in <digits> or in theleading or trailing <zeros>.Imagine an infinite 'virtual' string vdigits, consisting of thestring 'digits' (starting at index 0) padded on both the left andright with infinite strings of zeros. We want to output a slicevdigits[vdigits_start : vdigits_end]of this virtual string. Thus if vdigits_start < 0 then we'll endup producing some leading zeros; if vdigits_end > digits_len therewill be trailing zeros in the output. The next section of codedetermines whether to use an exponent or not, figures out theposition 'decpt' of the decimal point, and computes 'vdigits_start'and 'vdigits_end'. */vdigits_end = digits_len;switch (format_code) {case 'e':use_exp = 1;vdigits_end = precision;break;case 'f':vdigits_end = decpt + precision;break;case 'g':if (decpt <= -4 || decpt >(add_dot_0_if_integer ? precision-1 : precision))use_exp = 1;if (use_alt_formatting)vdigits_end = precision;break;case 'r':/* convert to exponential format at 1e16. We used to convertat 1e17, but that gives odd-looking results for some valueswhen a 16-digit 'shortest' repr is padded with bogus zeros.For example, repr(2e16+8) would give 20000000000000010.0;the true value is 20000000000000008.0. */if (decpt <= -4 || decpt > 16)use_exp = 1;break;default:PyErr_BadInternalCall();goto exit;}/* if using an exponent, reset decimal point position to 1 and adjustexponent accordingly.*/if (use_exp) {exp = (int)decpt - 1;decpt = 1;}/* ensure vdigits_start < decpt <= vdigits_end, or vdigits_start <decpt < vdigits_end if add_dot_0_if_integer and no exponent */vdigits_start = decpt <= 0 ? decpt-1 : 0;if (!use_exp && add_dot_0_if_integer)vdigits_end = vdigits_end > decpt ? vdigits_end : decpt + 1;elsevdigits_end = vdigits_end > decpt ? vdigits_end : decpt;/* double check inequalities */assert(vdigits_start <= 0 &&0 <= digits_len &&digits_len <= vdigits_end);/* decimal point should be in (vdigits_start, vdigits_end] */assert(vdigits_start < decpt && decpt <= vdigits_end);/* Compute an upper bound how much memory we need. This might be a fewchars too long, but no big deal. */bufsize =/* sign, decimal point and trailing 0 byte */3 +/* total digit count (including zero padding on both sides) */(vdigits_end - vdigits_start) +/* exponent "e+100", max 3 numerical digits */(use_exp ? 5 : 0);/* Now allocate the memory and initialize p to point to the start ofit. */buf = (char *)PyMem_Malloc(bufsize);if (buf == NULL) {PyErr_NoMemory();goto exit;}p = buf;/* Add a negative sign if negative, and a plus sign if non-negativeand always_add_sign is true. */if (sign == 1)*p++ = '-';else if (always_add_sign)*p++ = '+';/* note that exactly one of the three 'if' conditions is true,so we include exactly one decimal point *//* Zero padding on left of digit string */if (decpt <= 0) {memset(p, '0', decpt-vdigits_start);p += decpt - vdigits_start;*p++ = '.';memset(p, '0', 0-decpt);p += 0-decpt;}else {memset(p, '0', 0-vdigits_start);p += 0 - vdigits_start;}/* Digits, with included decimal point */if (0 < decpt && decpt <= digits_len) {strncpy(p, digits, decpt-0);p += decpt-0;*p++ = '.';strncpy(p, digits+decpt, digits_len-decpt);p += digits_len-decpt;}else {strncpy(p, digits, digits_len);p += digits_len;}/* And zeros on the right */if (digits_len < decpt) {memset(p, '0', decpt-digits_len);p += decpt-digits_len;*p++ = '.';memset(p, '0', vdigits_end-decpt);p += vdigits_end-decpt;}else {memset(p, '0', vdigits_end-digits_len);p += vdigits_end-digits_len;}/* Delete a trailing decimal pt unless using alternative formatting. */if (p[-1] == '.' && !use_alt_formatting)p--;/* Now that we've done zero padding, add an exponent if needed. */if (use_exp) {*p++ = float_strings[OFS_E][0];exp_len = sprintf(p, "%+.02d", exp);p += exp_len;}exit:if (buf) {*p = '0円';/* It's too late if this fails, as we've already stepped onmemory that isn't ours. But it's an okay debugging test. */assert(p-buf < bufsize);}if (digits)_Py_dg_freedtoa(digits);return buf;}char * PyOS_double_to_string(double val,char format_code,int precision,int flags,int *type){const char * const *float_strings = lc_float_strings;int mode;/* Validate format_code, and map upper and lower case. Compute themode and make any adjustments as needed. */switch (format_code) {/* exponent */case 'E':float_strings = uc_float_strings;format_code = 'e';/* Fall through. */case 'e':mode = 2;precision++;break;/* fixed */case 'F':float_strings = uc_float_strings;format_code = 'f';/* Fall through. */case 'f':mode = 3;break;/* general */case 'G':float_strings = uc_float_strings;format_code = 'g';/* Fall through. */case 'g':mode = 2;/* precision 0 makes no sense for 'g' format; interpret as 1 */if (precision == 0)precision = 1;break;/* repr format */case 'r':mode = 0;/* Supplied precision is unused, must be 0. */if (precision != 0) {PyErr_BadInternalCall();return NULL;}break;default:PyErr_BadInternalCall();return NULL;}return format_float_short(val, format_code, mode, precision,flags & Py_DTSF_SIGN,flags & Py_DTSF_ADD_DOT_0,flags & Py_DTSF_ALT,float_strings, type);}#endif /* ifdef PY_NO_SHORT_FLOAT_REPR */
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