/*
生产者,消费者。

多生产者,多消费者的问题。
if判断标记,只有一次,会导致不该运行的线程运行了。出现了数据错误的情况。
while判断标记,解决了线程获取执行权后,是否要运行!

notify:只能唤醒一个线程,如果本方唤醒了本方,没有意义。而且while判断标记+notify会导致死锁。
notifyAll解决了本方线程一定会唤醒对方线程的问题。


*/

class Resource
{
	private String name;
	private int count = 1;
	private boolean flag = false;
	public synchronized void set(String name)// 
	{
		while(flag)
			try{this.wait();}catch(InterruptedException e){}// t1 t0
		
		this.name = name + count;//烤鸭1 烤鸭2 烤鸭3
		count++;//2 3 4
		System.out.println(Thread.currentThread().getName()+"...生产者..."+this.name);//生产烤鸭1 生产烤鸭2 生产烤鸭3
		flag = true;
		notifyAll();
	}

	public synchronized void out()// t3
	{
		while(!flag)
			try{this.wait();}catch(InterruptedException e){}	//t2 t3
		System.out.println(Thread.currentThread().getName()+"...消费者........"+this.name);//消费烤鸭1
		flag = false;
		notifyAll();
	}
}

class Producer implements Runnable
{
	private Resource r;
	Producer(Resource r)
	{
		this.r = r;
	}
	public void run()
	{
		while(true)
		{
			r.set("烤鸭");
		}
	}
}

class Consumer implements Runnable
{
	private Resource r;
	Consumer(Resource r)
	{
		this.r = r;
	}
	public void run()
	{
		while(true)
		{
			r.out();
		}
	}
}



class ProducerConsumerDemo
{
	public static void main(String[] args) 
	{
		Resource r = new Resource();
		Producer pro = new Producer(r);
		Consumer con = new Consumer(r);

		Thread t0 = new Thread(pro);
		Thread t1 = new Thread(pro);
		Thread t2 = new Thread(con);
		Thread t3 = new Thread(con);
		t0.start();
		t1.start();
		t2.start();
		t3.start();

	}
}