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decision_tree.py 4.74 KB
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cclauss 提交于 2017年11月25日 17:23 +08:00 . Modernize Python 2 code to get ready for Python 3
"""
Implementation of a basic regression decision tree.
Input data set: The input data set must be 1-dimensional with continuous labels.
Output: The decision tree maps a real number input to a real number output.
"""
from __future__ import print_function
import numpy as np
class Decision_Tree:
def __init__(self, depth = 5, min_leaf_size = 5):
self.depth = depth
self.decision_boundary = 0
self.left = None
self.right = None
self.min_leaf_size = min_leaf_size
self.prediction = None
def mean_squared_error(self, labels, prediction):
"""
mean_squared_error:
@param labels: a one dimensional numpy array
@param prediction: a floating point value
return value: mean_squared_error calculates the error if prediction is used to estimate the labels
"""
if labels.ndim != 1:
print("Error: Input labels must be one dimensional")
return np.mean((labels - prediction) ** 2)
def train(self, X, y):
"""
train:
@param X: a one dimensional numpy array
@param y: a one dimensional numpy array.
The contents of y are the labels for the corresponding X values
train does not have a return value
"""
"""
this section is to check that the inputs conform to our dimensionality constraints
"""
if X.ndim != 1:
print("Error: Input data set must be one dimensional")
return
if len(X) != len(y):
print("Error: X and y have different lengths")
return
if y.ndim != 1:
print("Error: Data set labels must be one dimensional")
return
if len(X) < 2 * self.min_leaf_size:
self.prediction = np.mean(y)
return
if self.depth == 1:
self.prediction = np.mean(y)
return
best_split = 0
min_error = self.mean_squared_error(X,np.mean(y)) * 2
"""
loop over all possible splits for the decision tree. find the best split.
if no split exists that is less than 2 * error for the entire array
then the data set is not split and the average for the entire array is used as the predictor
"""
for i in range(len(X)):
if len(X[:i]) < self.min_leaf_size:
continue
elif len(X[i:]) < self.min_leaf_size:
continue
else:
error_left = self.mean_squared_error(X[:i], np.mean(y[:i]))
error_right = self.mean_squared_error(X[i:], np.mean(y[i:]))
error = error_left + error_right
if error < min_error:
best_split = i
min_error = error
if best_split != 0:
left_X = X[:best_split]
left_y = y[:best_split]
right_X = X[best_split:]
right_y = y[best_split:]
self.decision_boundary = X[best_split]
self.left = Decision_Tree(depth = self.depth - 1, min_leaf_size = self.min_leaf_size)
self.right = Decision_Tree(depth = self.depth - 1, min_leaf_size = self.min_leaf_size)
self.left.train(left_X, left_y)
self.right.train(right_X, right_y)
else:
self.prediction = np.mean(y)
return
def predict(self, x):
"""
predict:
@param x: a floating point value to predict the label of
the prediction function works by recursively calling the predict function
of the appropriate subtrees based on the tree's decision boundary
"""
if self.prediction is not None:
return self.prediction
elif self.left or self.right is not None:
if x >= self.decision_boundary:
return self.right.predict(x)
else:
return self.left.predict(x)
else:
print("Error: Decision tree not yet trained")
return None
def main():
"""
In this demonstration we're generating a sample data set from the sin function in numpy.
We then train a decision tree on the data set and use the decision tree to predict the
label of 10 different test values. Then the mean squared error over this test is displayed.
"""
X = np.arange(-1., 1., 0.005)
y = np.sin(X)
tree = Decision_Tree(depth = 10, min_leaf_size = 10)
tree.train(X,y)
test_cases = (np.random.rand(10) * 2) - 1
predictions = np.array([tree.predict(x) for x in test_cases])
avg_error = np.mean((predictions - test_cases) ** 2)
print("Test values: " + str(test_cases))
print("Predictions: " + str(predictions))
print("Average error: " + str(avg_error))
if __name__ == '__main__':
main()
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