# flake8: noqa

"""The following implementation assumes that the activities
are already sorted according to their finish time"""

"""Prints a maximum set of activities that can be done by a
single person, one at a time"""
# n --> Total number of activities
# start[]--> An array that contains start time of all activities
# finish[] --> An array that contains finish time of all activities


def printMaxActivities(start, finish):
 """
 >>> start = [1, 3, 0, 5, 8, 5]
 >>> finish = [2, 4, 6, 7, 9, 9]
 >>> printMaxActivities(start, finish)
 The following activities are selected:
 0 1 3 4 
 """
 n = len(finish)
 print("The following activities are selected:")

 # The first activity is always selected
 i = 0
 print(i, end=" ")

 # Consider rest of the activities
 for j in range(n):

 # If this activity has start time greater than
 # or equal to the finish time of previously
 # selected activity, then select it
 if start[j] >= finish[i]:
 print(j, end=" ")
 i = j


# Driver program to test above function
start = [1, 3, 0, 5, 8, 5]
finish = [2, 4, 6, 7, 9, 9]
printMaxActivities(start, finish)

"""
The following activities are selected:
0 1 3 4
"""