/** Copyright (c) 1998, 2017, Oracle and/or its affiliates. All rights reserved.* ORACLE PROPRIETARY/CONFIDENTIAL. Use is subject to license terms.*********************/package java.lang;/*** Port of the "Freely Distributable Math Library", version 5.3, from* C to Java.** <p>The C version of fdlibm relied on the idiom of pointer aliasing* a 64-bit double floating-point value as a two-element array of* 32-bit integers and reading and writing the two halves of the* double independently. This coding pattern was problematic to C* optimizers and not directly expressible in Java. Therefore, rather* than a memory level overlay, if portions of a double need to be* operated on as integer values, the standard library methods for* bitwise floating-point to integer conversion,* Double.longBitsToDouble and Double.doubleToRawLongBits, are directly* or indirectly used.** <p>The C version of fdlibm also took some pains to signal the* correct IEEE 754 exceptional conditions divide by zero, invalid,* overflow and underflow. For example, overflow would be signaled by* {@code huge * huge} where {@code huge} was a large constant that* would overflow when squared. Since IEEE floating-point exceptional* handling is not supported natively in the JVM, such coding patterns* have been omitted from this port. For example, rather than {@code* return huge * huge}, this port will use {@code return INFINITY}.** <p>Various comparison and arithmetic operations in fdlibm could be* done either based on the integer view of a value or directly on the* floating-point representation. Which idiom is faster may depend on* platform specific factors. However, for code clarity if no other* reason, this port will favor expressing the semantics of those* operations in terms of floating-point operations when convenient to* do so.*/class FdLibm {// Constants used by multiple algorithmsprivate static final double INFINITY = Double.POSITIVE_INFINITY;private FdLibm() {throw new UnsupportedOperationException("No FdLibm instances for you.");}/*** Return the low-order 32 bits of the double argument as an int.*/private static int __LO(double x) {long transducer = Double.doubleToRawLongBits(x);return (int)transducer;}/*** Return a double with its low-order bits of the second argument* and the high-order bits of the first argument..*/private static double __LO(double x, int low) {long transX = Double.doubleToRawLongBits(x);return Double.longBitsToDouble((transX & 0xFFFF_FFFF_0000_0000L) |(low & 0x0000_0000_FFFF_FFFFL));}/*** Return the high-order 32 bits of the double argument as an int.*/private static int __HI(double x) {long transducer = Double.doubleToRawLongBits(x);return (int)(transducer >> 32);}/*** Return a double with its high-order bits of the second argument* and the low-order bits of the first argument..*/private static double __HI(double x, int high) {long transX = Double.doubleToRawLongBits(x);return Double.longBitsToDouble((transX & 0x0000_0000_FFFF_FFFFL) |( ((long)high)) << 32 );}/*** cbrt(x)* Return cube root of x*/public static class Cbrt {// unsignedprivate static final int B1 = 715094163; /* B1 = (682-0.03306235651)*2**20 */private static final int B2 = 696219795; /* B2 = (664-0.03306235651)*2**20 */private static final double C = 0x1.15f15f15f15f1p-1; // 19/35 ~= 5.42857142857142815906e-01private static final double D = -0x1.691de2532c834p-1; // -864/1225 ~= 7.05306122448979611050e-01private static final double E = 0x1.6a0ea0ea0ea0fp0; // 99/70 ~= 1.41428571428571436819e+00private static final double F = 0x1.9b6db6db6db6ep0; // 45/28 ~= 1.60714285714285720630e+00private static final double G = 0x1.6db6db6db6db7p-2; // 5/14 ~= 3.57142857142857150787e-01private Cbrt() {throw new UnsupportedOperationException();}public static strictfp double compute(double x) {double t = 0.0;double sign;if (x == 0.0 || !Double.isFinite(x))return x; // Handles signed zeros properlysign = (x < 0.0) ? -1.0: 1.0;x = Math.abs(x); // x <- |x|// Rough cbrt to 5 bitsif (x < 0x1.0p-1022) { // subnormal numbert = 0x1.0p54; // set t= 2**54t *= x;t = __HI(t, __HI(t)/3 + B2);} else {int hx = __HI(x); // high word of xt = __HI(t, hx/3 + B1);}// New cbrt to 23 bits, may be implemented in single precisiondouble r, s, w;r = t * t/x;s = C + r*t;t *= G + F/(s + E + D/s);// Chopped to 20 bits and make it larger than cbrt(x)t = __LO(t, 0);t = __HI(t, __HI(t) + 0x00000001);// One step newton iteration to 53 bits with error less than 0.667 ulpss = t * t; // t*t is exactr = x / s;w = t + t;r = (r - t)/(w + r); // r-s is exactt = t + t*r;// Restore the original sign bitreturn sign * t;}}/*** hypot(x,y)** Method :* If (assume round-to-nearest) z = x*x + y*y* has error less than sqrt(2)/2 ulp, than* sqrt(z) has error less than 1 ulp (exercise).** So, compute sqrt(x*x + y*y) with some care as* follows to get the error below 1 ulp:** Assume x > y > 0;* (if possible, set rounding to round-to-nearest)* 1. if x > 2y use* x1*x1 + (y*y + (x2*(x + x1))) for x*x + y*y* where x1 = x with lower 32 bits cleared, x2 = x - x1; else* 2. if x <= 2y use* t1*y1 + ((x-y) * (x-y) + (t1*y2 + t2*y))* where t1 = 2x with lower 32 bits cleared, t2 = 2x - t1,* y1= y with lower 32 bits chopped, y2 = y - y1.** NOTE: scaling may be necessary if some argument is too* large or too tiny** Special cases:* hypot(x,y) is INF if x or y is +INF or -INF; else* hypot(x,y) is NAN if x or y is NAN.** Accuracy:* hypot(x,y) returns sqrt(x^2 + y^2) with error less* than 1 ulp (unit in the last place)*/public static class Hypot {public static final double TWO_MINUS_600 = 0x1.0p-600;public static final double TWO_PLUS_600 = 0x1.0p+600;private Hypot() {throw new UnsupportedOperationException();}public static strictfp double compute(double x, double y) {double a = Math.abs(x);double b = Math.abs(y);if (!Double.isFinite(a) || !Double.isFinite(b)) {if (a == INFINITY || b == INFINITY)return INFINITY;elsereturn a + b; // Propagate NaN significand bits}if (b > a) {double tmp = a;a = b;b = tmp;}assert a >= b;// Doing bitwise conversion after screening for NaN allows// the code to not worry about the possibility of// "negative" NaN values.// Note: the ha and hb variables are the high-order// 32-bits of a and b stored as integer values. The ha and// hb values are used first for a rough magnitude// comparison of a and b and second for simulating higher// precision by allowing a and b, respectively, to be// decomposed into non-overlapping portions. Both of these// uses could be eliminated. The magnitude comparison// could be eliminated by extracting and comparing the// exponents of a and b or just be performing a// floating-point divide. Splitting a floating-point// number into non-overlapping portions can be// accomplished by judicious use of multiplies and// additions. For details see T. J. Dekker, A Floating// Point Technique for Extending the Available Precision ,// Numerische Mathematik, vol. 18, 1971, pp.224-242 and// subsequent work.int ha = __HI(a); // high word of aint hb = __HI(b); // high word of bif ((ha - hb) > 0x3c00000) {return a + b; // x / y > 2**60}int k = 0;if (a > 0x1.00000_ffff_ffffp500) { // a > ~2**500// scale a and b by 2**-600ha -= 0x25800000;hb -= 0x25800000;a = a * TWO_MINUS_600;b = b * TWO_MINUS_600;k += 600;}double t1, t2;if (b < 0x1.0p-500) { // b < 2**-500if (b < Double.MIN_NORMAL) { // subnormal b or 0 */if (b == 0.0)return a;t1 = 0x1.0p1022; // t1 = 2^1022b *= t1;a *= t1;k -= 1022;} else { // scale a and b by 2^600ha += 0x25800000; // a *= 2^600hb += 0x25800000; // b *= 2^600a = a * TWO_PLUS_600;b = b * TWO_PLUS_600;k -= 600;}}// medium size a and bdouble w = a - b;if (w > b) {t1 = 0;t1 = __HI(t1, ha);t2 = a - t1;w = Math.sqrt(t1*t1 - (b*(-b) - t2 * (a + t1)));} else {double y1, y2;a = a + a;y1 = 0;y1 = __HI(y1, hb);y2 = b - y1;t1 = 0;t1 = __HI(t1, ha + 0x00100000);t2 = a - t1;w = Math.sqrt(t1*y1 - (w*(-w) - (t1*y2 + t2*b)));}if (k != 0) {return Math.powerOfTwoD(k) * w;} elsereturn w;}}/*** Compute x**y* n* Method: Let x = 2 * (1+f)* 1. Compute and return log2(x) in two pieces:* log2(x) = w1 + w2,* where w1 has 53 - 24 = 29 bit trailing zeros.* 2. Perform y*log2(x) = n+y' by simulating multi-precision* arithmetic, where |y'| <= 0.5.* 3. Return x**y = 2**n*exp(y'*log2)** Special cases:* 1. (anything) ** 0 is 1* 2. (anything) ** 1 is itself* 3. (anything) ** NAN is NAN* 4. NAN ** (anything except 0) is NAN* 5. +-(|x| > 1) ** +INF is +INF* 6. +-(|x| > 1) ** -INF is +0* 7. +-(|x| < 1) ** +INF is +0* 8. +-(|x| < 1) ** -INF is +INF* 9. +-1 ** +-INF is NAN* 10. +0 ** (+anything except 0, NAN) is +0* 11. -0 ** (+anything except 0, NAN, odd integer) is +0* 12. +0 ** (-anything except 0, NAN) is +INF* 13. -0 ** (-anything except 0, NAN, odd integer) is +INF* 14. -0 ** (odd integer) = -( +0 ** (odd integer) )* 15. +INF ** (+anything except 0,NAN) is +INF* 16. +INF ** (-anything except 0,NAN) is +0* 17. -INF ** (anything) = -0 ** (-anything)* 18. (-anything) ** (integer) is (-1)**(integer)*(+anything**integer)* 19. (-anything except 0 and inf) ** (non-integer) is NAN** Accuracy:* pow(x,y) returns x**y nearly rounded. In particular* pow(integer,integer)* always returns the correct integer provided it is* representable.*/public static class Pow {private Pow() {throw new UnsupportedOperationException();}public static strictfp double compute(final double x, final double y) {double z;double r, s, t, u, v, w;int i, j, k, n;// y == zero: x**0 = 1if (y == 0.0)return 1.0;// +/-NaN return x + y to propagate NaN significandsif (Double.isNaN(x) || Double.isNaN(y))return x + y;final double y_abs = Math.abs(y);double x_abs = Math.abs(x);// Special values of yif (y == 2.0) {return x * x;} else if (y == 0.5) {if (x >= -Double.MAX_VALUE) // Handle x == -infinity laterreturn Math.sqrt(x + 0.0); // Add 0.0 to properly handle x == -0.0} else if (y_abs == 1.0) { // y is +/-1return (y == 1.0) ? x : 1.0 / x;} else if (y_abs == INFINITY) { // y is +/-infinityif (x_abs == 1.0)return y - y; // inf**+/-1 is NaNelse if (x_abs > 1.0) // (|x| > 1)**+/-inf = inf, 0return (y >= 0) ? y : 0.0;else // (|x| < 1)**-/+inf = inf, 0return (y < 0) ? -y : 0.0;}final int hx = __HI(x);int ix = hx & 0x7fffffff;/** When x < 0, determine if y is an odd integer:* y_is_int = 0 ... y is not an integer* y_is_int = 1 ... y is an odd int* y_is_int = 2 ... y is an even int*/int y_is_int = 0;if (hx < 0) {if (y_abs >= 0x1.0p53) // |y| >= 2^53 = 9.007199254740992E15y_is_int = 2; // y is an even integer since ulp(2^53) = 2.0else if (y_abs >= 1.0) { // |y| >= 1.0long y_abs_as_long = (long) y_abs;if ( ((double) y_abs_as_long) == y_abs) {y_is_int = 2 - (int)(y_abs_as_long & 0x1L);}}}// Special value of xif (x_abs == 0.0 ||x_abs == INFINITY ||x_abs == 1.0) {z = x_abs; // x is +/-0, +/-inf, +/-1if (y < 0.0)z = 1.0/z; // z = (1/|x|)if (hx < 0) {if (((ix - 0x3ff00000) | y_is_int) == 0) {z = (z-z)/(z-z); // (-1)**non-int is NaN} else if (y_is_int == 1)z = -1.0 * z; // (x < 0)**odd = -(|x|**odd)}return z;}n = (hx >> 31) + 1;// (x < 0)**(non-int) is NaNif ((n | y_is_int) == 0)return (x-x)/(x-x);s = 1.0; // s (sign of result -ve**odd) = -1 else = 1if ( (n | (y_is_int - 1)) == 0)s = -1.0; // (-ve)**(odd int)double p_h, p_l, t1, t2;// |y| is hugeif (y_abs > 0x1.00000_ffff_ffffp31) { // if |y| > ~2**31final double INV_LN2 = 0x1.7154_7652_b82fep0; // 1.44269504088896338700e+00 = 1/ln2final double INV_LN2_H = 0x1.715476p0; // 1.44269502162933349609e+00 = 24 bits of 1/ln2final double INV_LN2_L = 0x1.4ae0_bf85_ddf44p-26; // 1.92596299112661746887e-08 = 1/ln2 tail// Over/underflow if x is not close to oneif (x_abs < 0x1.fffff_0000_0000p-1) // |x| < ~0.9999995231628418return (y < 0.0) ? s * INFINITY : s * 0.0;if (x_abs > 0x1.00000_ffff_ffffp0) // |x| > ~1.0return (y > 0.0) ? s * INFINITY : s * 0.0;/** now |1-x| is tiny <= 2**-20, sufficient to compute* log(x) by x - x^2/2 + x^3/3 - x^4/4*/t = x_abs - 1.0; // t has 20 trailing zerosw = (t * t) * (0.5 - t * (0.3333333333333333333333 - t * 0.25));u = INV_LN2_H * t; // INV_LN2_H has 21 sig. bitsv = t * INV_LN2_L - w * INV_LN2;t1 = u + v;t1 =__LO(t1, 0);t2 = v - (t1 - u);} else {final double CP = 0x1.ec70_9dc3_a03fdp-1; // 9.61796693925975554329e-01 = 2/(3ln2)final double CP_H = 0x1.ec709ep-1; // 9.61796700954437255859e-01 = (float)cpfinal double CP_L = -0x1.e2fe_0145_b01f5p-28; // -7.02846165095275826516e-09 = tail of CP_Hdouble z_h, z_l, ss, s2, s_h, s_l, t_h, t_l;n = 0;// Take care of subnormal numbersif (ix < 0x00100000) {x_abs *= 0x1.0p53; // 2^53 =わ 9007199254740992.0n -= 53;ix = __HI(x_abs);}n += ((ix) >> 20) - 0x3ff;j = ix & 0x000fffff;// Determine intervalix = j | 0x3ff00000; // Normalize ixif (j <= 0x3988E)k = 0; // |x| <sqrt(3/2)else if (j < 0xBB67A)k = 1; // |x| <sqrt(3)else {k = 0;n += 1;ix -= 0x00100000;}x_abs = __HI(x_abs, ix);// Compute ss = s_h + s_l = (x-1)/(x+1) or (x-1.5)/(x+1.5)final double BP[] = {1.0,1.5};final double DP_H[] = {0.0,0x1.2b80_34p-1}; // 5.84962487220764160156e-01final double DP_L[] = {0.0,0x1.cfde_b43c_fd006p-27};// 1.35003920212974897128e-08// Poly coefs for (3/2)*(log(x)-2s-2/3*s**3final double L1 = 0x1.3333_3333_33303p-1; // 5.99999999999994648725e-01final double L2 = 0x1.b6db_6db6_fabffp-2; // 4.28571428578550184252e-01final double L3 = 0x1.5555_5518_f264dp-2; // 3.33333329818377432918e-01final double L4 = 0x1.1746_0a91_d4101p-2; // 2.72728123808534006489e-01final double L5 = 0x1.d864_a93c_9db65p-3; // 2.30660745775561754067e-01final double L6 = 0x1.a7e2_84a4_54eefp-3; // 2.06975017800338417784e-01u = x_abs - BP[k]; // BP[0]=1.0, BP[1]=1.5v = 1.0 / (x_abs + BP[k]);ss = u * v;s_h = ss;s_h = __LO(s_h, 0);// t_h=x_abs + BP[k] Hight_h = 0.0;t_h = __HI(t_h, ((ix >> 1) | 0x20000000) + 0x00080000 + (k << 18) );t_l = x_abs - (t_h - BP[k]);s_l = v * ((u - s_h * t_h) - s_h * t_l);// Compute log(x_abs)s2 = ss * ss;r = s2 * s2* (L1 + s2 * (L2 + s2 * (L3 + s2 * (L4 + s2 * (L5 + s2 * L6)))));r += s_l * (s_h + ss);s2 = s_h * s_h;t_h = 3.0 + s2 + r;t_h = __LO(t_h, 0);t_l = r - ((t_h - 3.0) - s2);// u+v = ss*(1+...)u = s_h * t_h;v = s_l * t_h + t_l * ss;// 2/(3log2)*(ss + ...)p_h = u + v;p_h = __LO(p_h, 0);p_l = v - (p_h - u);z_h = CP_H * p_h; // CP_H + CP_L = 2/(3*log2)z_l = CP_L * p_h + p_l * CP + DP_L[k];// log2(x_abs) = (ss + ..)*2/(3*log2) = n + DP_H + z_h + z_lt = (double)n;t1 = (((z_h + z_l) + DP_H[k]) + t);t1 = __LO(t1, 0);t2 = z_l - (((t1 - t) - DP_H[k]) - z_h);}// Split up y into (y1 + y2) and compute (y1 + y2) * (t1 + t2)double y1 = y;y1 = __LO(y1, 0);p_l = (y - y1) * t1 + y * t2;p_h = y1 * t1;z = p_l + p_h;j = __HI(z);i = __LO(z);if (j >= 0x40900000) { // z >= 1024if (((j - 0x40900000) | i)!=0) // if z > 1024return s * INFINITY; // Overflowelse {final double OVT = 8.0085662595372944372e-0017; // -(1024-log2(ovfl+.5ulp))if (p_l + OVT > z - p_h)return s * INFINITY; // Overflow}} else if ((j & 0x7fffffff) >= 0x4090cc00 ) { // z <= -1075if (((j - 0xc090cc00) | i)!=0) // z < -1075return s * 0.0; // Underflowelse {if (p_l <= z - p_h)return s * 0.0; // Underflow}}/** Compute 2**(p_h+p_l)*/// Poly coefs for (3/2)*(log(x)-2s-2/3*s**3final double P1 = 0x1.5555_5555_5553ep-3; // 1.66666666666666019037e-01final double P2 = -0x1.6c16_c16b_ebd93p-9; // -2.77777777770155933842e-03final double P3 = 0x1.1566_aaf2_5de2cp-14; // 6.61375632143793436117e-05final double P4 = -0x1.bbd4_1c5d_26bf1p-20; // -1.65339022054652515390e-06final double P5 = 0x1.6376_972b_ea4d0p-25; // 4.13813679705723846039e-08final double LG2 = 0x1.62e4_2fef_a39efp-1; // 6.93147180559945286227e-01final double LG2_H = 0x1.62e43p-1; // 6.93147182464599609375e-01final double LG2_L = -0x1.05c6_10ca_86c39p-29; // -1.90465429995776804525e-09i = j & 0x7fffffff;k = (i >> 20) - 0x3ff;n = 0;if (i > 0x3fe00000) { // if |z| > 0.5, set n = [z + 0.5]n = j + (0x00100000 >> (k + 1));k = ((n & 0x7fffffff) >> 20) - 0x3ff; // new k for nt = 0.0;t = __HI(t, (n & ~(0x000fffff >> k)) );n = ((n & 0x000fffff) | 0x00100000) >> (20 - k);if (j < 0)n = -n;p_h -= t;}t = p_l + p_h;t = __LO(t, 0);u = t * LG2_H;v = (p_l - (t - p_h)) * LG2 + t * LG2_L;z = u + v;w = v - (z - u);t = z * z;t1 = z - t * (P1 + t * (P2 + t * (P3 + t * (P4 + t * P5))));r = (z * t1)/(t1 - 2.0) - (w + z * w);z = 1.0 - (r - z);j = __HI(z);j += (n << 20);if ((j >> 20) <= 0)z = Math.scalb(z, n); // subnormal outputelse {int z_hi = __HI(z);z_hi += (n << 20);z = __HI(z, z_hi);}return s * z;}}/*** Returns the exponential of x.** Method* 1. Argument reduction:* Reduce x to an r so that |r| <= 0.5*ln2 ~ 0.34658.* Given x, find r and integer k such that** x = k*ln2 + r, |r| <= 0.5*ln2.** Here r will be represented as r = hi-lo for better* accuracy.** 2. Approximation of exp(r) by a special rational function on* the interval [0,0.34658]:* Write* R(r**2) = r*(exp(r)+1)/(exp(r)-1) = 2 + r*r/6 - r**4/360 + ...* We use a special Reme algorithm on [0,0.34658] to generate* a polynomial of degree 5 to approximate R. The maximum error* of this polynomial approximation is bounded by 2**-59. In* other words,* R(z) ~ 2.0 + P1*z + P2*z**2 + P3*z**3 + P4*z**4 + P5*z**5* (where z=r*r, and the values of P1 to P5 are listed below)* and* | 5 | -59* | 2.0+P1*z+...+P5*z - R(z) | <= 2* | |* The computation of exp(r) thus becomes* 2*r* exp(r) = 1 + -------* R - r* r*R1(r)* = 1 + r + ----------- (for better accuracy)* 2 - R1(r)* where* 2 4 10* R1(r) = r - (P1*r + P2*r + ... + P5*r ).** 3. Scale back to obtain exp(x):* From step 1, we have* exp(x) = 2^k * exp(r)** Special cases:* exp(INF) is INF, exp(NaN) is NaN;* exp(-INF) is 0, and* for finite argument, only exp(0)=1 is exact.** Accuracy:* according to an error analysis, the error is always less than* 1 ulp (unit in the last place).** Misc. info.* For IEEE double* if x > 7.09782712893383973096e+02 then exp(x) overflow* if x < -7.45133219101941108420e+02 then exp(x) underflow** Constants:* The hexadecimal values are the intended ones for the following* constants. The decimal values may be used, provided that the* compiler will convert from decimal to binary accurately enough* to produce the hexadecimal values shown.*/static class Exp {private static final double one = 1.0;private static final double[] half = {0.5, -0.5,};private static final double huge = 1.0e+300;private static final double twom1000= 0x1.0p-1000; // 9.33263618503218878990e-302 = 2^-1000private static final double o_threshold= 0x1.62e42fefa39efp9; // 7.09782712893383973096e+02private static final double u_threshold= -0x1.74910d52d3051p9; // -7.45133219101941108420e+02;private static final double[] ln2HI ={ 0x1.62e42feep-1, // 6.93147180369123816490e-01-0x1.62e42feep-1}; // -6.93147180369123816490e-01private static final double[] ln2LO ={ 0x1.a39ef35793c76p-33, // 1.90821492927058770002e-10-0x1.a39ef35793c76p-33}; // -1.90821492927058770002e-10private static final double invln2 = 0x1.71547652b82fep0; // 1.44269504088896338700e+00private static final double P1 = 0x1.555555555553ep-3; // 1.66666666666666019037e-01private static final double P2 = -0x1.6c16c16bebd93p-9; // -2.77777777770155933842e-03private static final double P3 = 0x1.1566aaf25de2cp-14; // 6.61375632143793436117e-05private static final double P4 = -0x1.bbd41c5d26bf1p-20; // -1.65339022054652515390e-06private static final double P5 = 0x1.6376972bea4d0p-25; // 4.13813679705723846039e-08private Exp() {throw new UnsupportedOperationException();}// should be able to forgo strictfp due to controlled over/underflowpublic static strictfp double compute(double x) {double y;double hi = 0.0;double lo = 0.0;double c;double t;int k = 0;int xsb;/*unsigned*/ int hx;hx = __HI(x); /* high word of x */xsb = (hx >> 31) & 1; /* sign bit of x */hx &= 0x7fffffff; /* high word of |x| *//* filter out non-finite argument */if (hx >= 0x40862E42) { /* if |x| >= 709.78... */if (hx >= 0x7ff00000) {if (((hx & 0xfffff) | __LO(x)) != 0)return x + x; /* NaN */elsereturn (xsb == 0) ? x : 0.0; /* exp(+-inf) = {inf, 0} */}if (x > o_threshold)return huge * huge; /* overflow */if (x < u_threshold) // unsigned compare needed here?return twom1000 * twom1000; /* underflow */}/* argument reduction */if (hx > 0x3fd62e42) { /* if |x| > 0.5 ln2 */if(hx < 0x3FF0A2B2) { /* and |x| < 1.5 ln2 */hi = x - ln2HI[xsb];lo=ln2LO[xsb];k = 1 - xsb - xsb;} else {k = (int)(invln2 * x + half[xsb]);t = k;hi = x - t*ln2HI[0]; /* t*ln2HI is exact here */lo = t*ln2LO[0];}x = hi - lo;} else if (hx < 0x3e300000) { /* when |x|<2**-28 */if (huge + x > one)return one + x; /* trigger inexact */} else {k = 0;}/* x is now in primary range */t = x * x;c = x - t*(P1 + t*(P2 + t*(P3 + t*(P4 + t*P5))));if (k == 0)return one - ((x*c)/(c - 2.0) - x);elsey = one - ((lo - (x*c)/(2.0 - c)) - hi);if(k >= -1021) {y = __HI(y, __HI(y) + (k << 20)); /* add k to y's exponent */return y;} else {y = __HI(y, __HI(y) + ((k + 1000) << 20)); /* add k to y's exponent */return y * twom1000;}}}}
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