How to convert all shapefiles in folder into KML using ArcPy?

Question

I was trying to convert all the shp in a folder into kml.

featureclasses = arcpy.ListFeatureClasses()

for fc in featureclasses:

 # Set Local Variables
 composite = 'COMPOSITE'
 pixels = 1024
 dpi = 96
 clamped = 'CLAMPED_TO_GROUND'
 scale = 1
 outKML = fc[:-4] + ".kmz"
 arcpy.LayerToKML_conversion(fc,outKML, scale, composite,'', pixels, dpi, clamped)

It always says Failed to execute. Parameters are not valid. ERROR 000732: Layer: Dataset ZZZ.shp does not exist or is not supported Failed to execute (LayerToKML).

But I can manually do it within ArcMap 10.1 Desktop...

• artwork21: Welcome to GIS SE, are you defining an workspace directory before your loop?
• Mingshu: Yes, I did. But I looks that is not the problem

Answer 1

This is because the Layer to KML tool takes either LAYERS (feature layers in a map for example), or LAYER FILES (.lyr files on disk pointing at featureclasses).

If you want to run this as a script outside of ArcMap you'll have to run MakeFeatureLayer on every shapefile, turning them into a layer first and pass that onto Layer to KML.

This is starter code...you'll have to modify it to make unique names. As-is it'll overwrite each KMZ it outputs.

featureclasses = arcpy.ListFeatureClasses()
for fc in featureclasses:
 arcpy.MakeFeatureLayer_management(fc, "name1")
 arcpy.LayerToKML_conversion("name1", r"c:\temp\foo1.kmz")

• Mingshu: I added MakeFeatureLayer on every shapefile, but the same error was raised.
• KHibma: I added code. It should be enough to get you started