Finding features based on total overlap of another feature class using ArcGIS Pro

Question

I have 2 polygon feature class's (A and B) that overlap each other.

I want to select all the polygons of feature class A where the total overlapping area of feature class B polygons is less than 10m2 using ArcGIS Pro.

There may be multiple polygons overlapping

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I was able to do this when there is only 1 overlapping by doing this:

1. Union of feature class A and B
2. Clip the union output with Class A feature class as clip feature
3. Definition query on the output to only show polygons with an area less than 10m2
4. Select by location on feature class a with step 3 output as the intersecting feature

But I am not sure how to do this when there are more than 1 polygons of feature class B overlapping feature class A

• FelixIP: Intersect. Summarise area in output by b polygon id. John to b table.
• JUNGLE: Thanks, This worked.
• Hornbydd: @FelixIP -See your comment above- "John to b table"? Who is John? :)
• FelixIP: @Hornbydd I meant Sean. Does this sound better?

Answer 1

Since you are not concerned with which of the B geoms overlap the target A geom, you might try a different approach:

1) Calculate the area of each feature in A -> OrigArea

2) Get the difference of A and B (using B as the overlay) -> Difference

3) Calculate the area of each feature in Difference output -> NewArea

4) Compute Delta = OrigArea-NewArea

5) Join the Difference.Delta column back to A and select where Delta < 10m2

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• FelixIP: What software is it?
• OGmaps: Hi @FelixIP, the images are from a quick QGIS mockup. I don't currently have an ArcDesktop license but I thought a generic approach might still be helpful.
• FelixIP: Unfortunately terminology is too different, I struggle to understand. Why do you need original area anyway?
• OGmaps: @FelixIP, I get the original area of features in A so that I have it in the output of the Difference operation. That way its just OrigArea-CurrentAreaOfPolygon to get the total overlapping area of features in B.