Creating tfb file in Python Toolbox?

Question

What tool does:

Simply creates tbf file from raster extent.

What is the problem:

I ran toolbox in ArcMap 10.5.1 and ArcGIS Pro 2.2.4.

When I run it as standalone script it is working just fine.

I am not new to Python nor Python Toolboxes, but today:

1) I received an error which I never encountered before (error shown below)

2) when I declare rasters = arcpy.ListRasters('tif'), list of rasters is empty.

Error code:

Running script Tool...

Traceback (most recent call last): File "", line 54, in execute File "c:\program files\arcgis\pro\Resources\arcpy\arcpy\geoprocessing_base.py", line 527, in set_ self[env] = val File "c:\program files\arcgis\pro\Resources\arcpy\arcpy\geoprocessing_base.py", line 587, in setitem ret_ = setattr(self._gp, item, value) enter code here

RuntimeError: Object: Error in accessing environment Failed to execute (Tool).

Tool code below:

import arcpy
import os
class Toolbox(object):
 def __init__(self):
 """Define the toolbox (the name of the toolbox is the name of the
 .pyt file)."""
 self.label = "tfb file generator"
 self.alias = ""
 # List of tool classes associated with this toolbox
 self.tools = [Tool]
class Tool(object):
 def __init__(self):
 """Define the tool (tool name is the name of the class)."""
 self.label = "Generating tbf files"
 self.description = ""
 self.canRunInBackground = True
 def getParameterInfo(self):
 """Define parameter definitions"""
 # Pierwszy parametr
 inside = arcpy.Parameter(
 displayName="In workspace",
 name="in_gdb",
 datatype="DEWorkspace",
 parameterType="Required",
 direction="Input")
 p = [inside]
 return p
 def isLicensed(self):
 """Set whether tool is licensed to execute."""
 return True
 def updateParameters(self, parameters):
 """Modify the values and properties of parameters before internal
 validation is performed. This method is called whenever a parameter
 has been changed."""
 return
 def updateMessages(self, parameters):
 """Modify the messages created by internal validation for each tool
 parameter. This method is called after internal validation."""
 return
 def execute(self, parameters, messages):
 """The source code of the tool."""
 arcpy.env.overwriteOutput = True
 arcpy.env.workspace = parameters[0].valueAsText
 output = parameters[0].valueAsText
 rasters = arcpy.ListRasters('*.tif')
 i=1
 for ras in rasters:
 arcpy.AddMessage('Working on raster nr: {0} of {1} '.format(i, len(rasters)))
 f = arcpy.Raster(ras).extent
 north = f.YMax
 west = f.XMin
 south = f.YMin
 east = f.XMax
 i+= 1
 ras_split=ras.split('.')[0]
 with open(os.path.join(output,'{0}.tfb'.format(ras_split)), "w+") as text_file:
 text_file.write('north={0}\n'.format(north))
 text_file.write('west={0}\n'.format(west))
 text_file.write('south={0}\n'.format(south))
 text_file.write('east={0}'.format(east))
 return

---

Fixed all mistakes - tool fully working.

• PolyGeo: What is a tfb (or is it tbf) file?
• JuniorPythonNewbie: Tbh, I know only my client need to generate hundreds of tfb files for his tiffs. He is using them for this purpose I guess: rolands.com/jtls/j_designs/JTLS-2015-12485.pdf

Answer 1

arcpy.env.workspace = parameters[0] should be arcpy.env.workspace = parameters[0].valueAsText.

You are setting the workspace to a Parameter object, not a string, see Accessing parameters within a Python toolbox

Your rasters = arcpy.ListRasters('tif') will find only rasters called exactly "tif". If you want to find rasters with a .tif file extension, use rasters = arcpy.ListRasters('*.tif')