Parameter variable in expression for Calculate Field Python Script?

Question

Here is what I have

import arcpy
inputFC = arcpy.GetParameterAsText (0) #Feature Class 
inputField = arcpy.GetParameterAsText (1) #Field to manipulate 
inputChar = arcpy.GetParameterAsText (2) #The character(s) I wish to replace 
replChar = arcpy.GetParameterAsText (3) #The character(s) I wish to replace them with 
arcpy.CalculateField_management(inputFC, inputField, !inputField!.replace(inputChar, replChar), "PYTHON_9.3")

I am trying to use the "CalculateField_management" tool with a variable instead of a direct field for the 3rd input like I am with the first 2, but I can't seem to fit it in with the expression. I want it to take the value of the existing string and replace the characters I desire. How is the expression supposed to be written?

I have tried a variety of ways and can't figure it out.
For example: !inputField!.replace, '"!inputField!'".replace, inputField.replace, '"inputField"'.replace, etc.

Answer 1

You're on the right track with '"!inputField!'".replace, just needed some variable substitution. Otherwise, you'd just be operating on the value contained by the variable, eg "myField".replace('abc', 'def') which doesn't have much meaning.

So, you need to create a string, which is easy with string formatting.

inputField= 'myField'
inputChar = 'abc'
replChar = 'def'
expr = "!{field}!.replace('{old}', '{new}')".format(field=inputField,
 old=inputChar,
 new=replChar)
arcpy.CalculateField_management(inputFC, inputField, expr, "PYTHON_9.3")
>>> expr
"!myField!.replace('abc', 'def')" 
>>> print(expr)
!myField!.replace('abc', 'def')

Tricky to write, so I prefer cursors:

with arcpy.da.UpdateCursor(inputFC, inputField) as cursor:
 for row in cursor:
 new = row[0].replace(inputChar, replChar)
 cursor.updateRow([new])

• Maxwell Tougas: The UpdateCursor works great. I tried fiddling around with it previously and couldn't figure it out so thanks a lot. :)