How to connect push button in dock widget form?

Question

Following this tutorial as a guide, I created a plugin using the Plugin Builder with the dock widget form. I am now trying to connect a pushButton to a function. The following is a snippet of code:

def __init__(self, iface):
 self.dockwidget.pushButton.clicked.connect(self.test_print)
def test_print(self):
 print 'It works!'

However, I receive an:

error when calling its classFactory() method

I have also tried:

def initGui(self):
 QObject.connect(self.dockwidget.pushButton, SIGNAL("clicked()"), self.test_print)

But then there's an error calling its initGui() method. Any pointers?

---

Edit:

I have tried the following variations in the run(self) function, I no longer receive errors but nothing is printed in the console:

def run(self):
 #self.dockwidget.connect(self.dockwidget.pushButton,SIGNAL("clicked()"),self.test_print)
 #self.dockwidget.pushButton.clicked.connect(self.test_print)
 QObject.connect(self.dockwidget.ui.pushButton, SIGNAL("clicked()"), self.test_print)

• WKT: Did you try to put the connect in the run(self) method ?
• Joseph: @Azimo - Thanks, just tested it. I no longer receive the errors but nothing is printed in the console.
• WKT: QgsMessageLog.logMessage('It works!','test') ??
• Joseph: @Azimo - Not showing up when clicking the pushButton unfortunately. Works fine if I stick it in the run(self) function, which just loads the message log so atleast something happens!
• WKT: But, can you confirm that the "objectName" property of the QPushButton (in your .ui file) is "pushButton".

Answer 1

import os
from PyQt4 import QtGui, uic
from PyQt4.QtCore import pyqtSignal
FORM_CLASS, _ = uic.loadUiType(os.path.join(
 os.path.dirname(__file__), 'my_dockwidget_base.ui'))
class myDockWidget(QtGui.QDockWidget, FORM_CLASS):
 closingPlugin = pyqtSignal()
 def __init__(self, parent=None):
 """Constructor."""
 super(myDockWidget, self).__init__(parent)
 # Set up the user interface from Designer.
 # After setupUI you can access any designer object by doing
 # self.<objectname>, and you can use autoconnect slots - see
 # http://qt-project.org/doc/qt-4.8/designer-using-a-ui-file.html
 # #widgets-and-dialogs-with-auto-connect
 self.setupUi(self)
 def closeEvent(self, event):
 self.closingPlugin.emit()
 event.accept()

---

from PyQt4.QtCore import * #QSettings, QTranslator, qVersion, QCoreApplication, Qt
from PyQt4.QtGui import * #QAction, QIcon
from qgis.core import *
# Initialize Qt resources from file resources.py
import resources
# Import the code for the DockWidget
from my_dockwidget import myDockWidget
import os.path
class myPlugin:
 # cutting other methods (__init__, initGui, unload..etc..)
 def run(self):
 if not self.pluginIsActive:
 self.pluginIsActive = True
 # openOtherWin is outside of run method...
 self.dockwidget.but_openOtherWin.clicked.connect(self.openOtherWin)

---

• Joseph: Thanks for posting, I will try testing this at some point!
• WKT: Ok... Adding now the .py of plugin class ...
• Joseph: I created a test plugin and used your method and it worked. Interesting, I will accept your answer but will also keep mine in case it could work for others ;)

Answer 2

Guess the answer was simpler than I thought. Had to insert everything into the run(self) function. So the following code works:

def run(self):
 def test_print():
 print 'It works!'
 self.dockwidget.pushButton.clicked.connect(test_print)

• WKT: Not for me, strange.... :/
• Joseph: @Azimo - Haha indeed, were you also using dockwidgets or a dialog form?
• WKT: dock... I copy .py in an answer and will delete after...
• Joseph: @Azimo - Keep the answer in please. If it works for you then it could work for others in a similar situation ;)