Talk:Automatic vectorization
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The free() statements in the following example code engages in undefined behavior because the pointers received from malloc() have been altered. Segment faults, or other abnormal terminations, would be expected.
int *a = malloc(128*sizeof(int)); int *b = malloc(128*sizeof(int)); // initialize b for (i = 0; i<128; i++, a++, b++) *a = *b + 5; // ... // ... // ... free(b); free(a);
A very simple fix changes the following two lines:
for (i = 0; i<128; i++ ) a[i] = b[i] + 5;
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