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Normal function

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Function of ordinals in mathematics
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(March 2024)

In axiomatic set theory, a function f : Ord → Ord is called normal (or a normal function) if it is continuous (with respect to the order topology) and strictly monotonically increasing. This is equivalent to the following two conditions:

  1. For every limit ordinal γ (i.e. γ is neither zero nor a successor), it is the case that f (γ) = sup{f (ν) : ν < γ}.
  2. For all ordinals α < β, it is the case that f (α) < f (β).

Examples

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A simple normal function is given by f (α) = 1 + α (see ordinal arithmetic). But f (α) = α + 1 is not normal because it is not continuous at any limit ordinal (for example, f ( ω ) = ω + 1 ω = sup { f ( n ) : n < ω } {\displaystyle f(\omega )=\omega +1\neq \omega =\sup\{f(n):n<\omega \}} {\displaystyle f(\omega )=\omega +1\neq \omega =\sup\{f(n):n<\omega \}}). If β is a fixed ordinal, then the functions f (α) = β + α, f (α) = β ×ばつ α (for β ≥ 1), and f (α) = βα (for β ≥ 2) are all normal.

More important examples of normal functions are given by the aleph numbers f ( α ) = α {\displaystyle f(\alpha )=\aleph _{\alpha }} {\displaystyle f(\alpha )=\aleph _{\alpha }}, which connect ordinal and cardinal numbers, and by the beth numbers f ( α ) = α {\displaystyle f(\alpha )=\beth _{\alpha }} {\displaystyle f(\alpha )=\beth _{\alpha }}.

Properties

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If f is normal, then for any ordinal α,

f (α) ≥ α.[1]

Proof: If not, choose γ minimal such that f (γ) < γ. Since f is strictly monotonically increasing, f (f (γ)) < f (γ), contradicting minimality of γ.

Furthermore, for any non-empty set S of ordinals, we have

f (sup S) = sup f (S).

Proof: "≥" follows from the monotonicity of f and the definition of the supremum. For "", consider three cases:

  • if sup S = 0, then S = {0} and sup f (S) = f (0) = f (sup S);
  • if sup S = ν + 1 is a successor, then sup S is in S, so f (sup S) is in f (S), i.e. f (sup S) ≤ sup f (S);
  • if sup S is a nonzero limit, then for any ν < sup S there exists an s in S such that ν < s, i.e. f (ν) < f (s) ≤ sup f (S), yielding f (sup S) = sup {f (ν) : ν < sup S} ≤ sup f (S).

Every normal function f has arbitrarily large fixed points; see the fixed-point lemma for normal functions for a proof. One can create a normal function f ′ : Ord → Ord, called the derivative of f, such that f ′(α) is the α-th fixed point of f.[2] For a hierarchy of normal functions, see Veblen functions.

Notes

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  1. ^ Johnstone 1987, Exercise 6.9, p. 77
  2. ^ Johnstone 1987, Exercise 6.9, p. 77

References

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