2023 Cranbrook Tennis Classic – Singles
Appearance
From Wikipedia, the free encyclopedia
Singles | |
---|---|
2023 Cranbrook Tennis Classic | |
Final | |
Champion | United States Steve Johnson |
Runner-up | Kazakhstan Mikhail Kukushkin |
Score | 6–4, 6–7(7–9), 7–6(7–4) |
Events | |
2023 tennis event results
Main article: 2023 Cranbrook Tennis Classic
This was the first edition of the tournament.[1]
Steve Johnson won the title after defeating Mikhail Kukushkin 6–4, 6–7(7–9), 7–6(7–4) in the final.
Seeds
[edit ]- Australia James Duckworth (second round)
- Ecuador Emilio Gómez (second round)
- United States Denis Kudla (quarterfinals)
- Turkey Altuğ Çelikbilek (second round)
- Canada Alexis Galarneau (second round)
- France Giovanni Mpetshi Perricard (second round)
- United States Steve Johnson (champion)
- Australia Dane Sweeny (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
Kazakhstan Mikhail Kukushkin
4
79
64
7
United States Steve Johnson
6
67
77
Q
Australia Tristan Schoolkate
4
2
7
United States Steve Johnson
6
6
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
1
Australia J Duckworth
77
7
6
France G Mpetshi Perricard
3
6
6
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
References
[edit ]- ^ "Cranbrook hosts pro tennis tournament July 2-9". downtownpublications. May 19, 2023.