2018 St. Petersburg Open – Doubles
From Wikipedia, the free encyclopedia
| Doubles | |
|---|---|
| 2018 St. Petersburg Open | |
| Final | |
| Champions | Italy Matteo Berrettini Italy Fabio Fognini |
| Runners-up | Czech Republic Roman Jebavý Netherlands Matwé Middelkoop |
| Score | 7–6(8–6), 7–6(7–4) |
| Events | |
2018 tennis event results
Main article: 2018 St. Petersburg Open
Roman Jebavý and Matwé Middelkoop were the defending champions, but lost in the final to Matteo Berrettini and Fabio Fognini, 6–7(6–8), 6–7(4–7).
Seeds
[edit ]- United Kingdom Dominic Inglot / Croatia Franko Škugor (first round)
- Chile Julio Peralta / Argentina Horacio Zeballos (semifinals)
- Czech Republic Roman Jebavý / Netherlands Matwé Middelkoop (final)
- Sweden Robert Lindstedt / United States Rajeev Ram (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round
Quarterfinals
Semifinals
Final
Bosnia and Herzegovina M Bašić
Bosnia and Herzegovina D Džumhur 3 61 Italy M Berrettini
Italy F Fognini 78 77
Bosnia and Herzegovina D Džumhur 3 61 Italy M Berrettini
Italy F Fognini 78 77
Poland M Matkowski
United States N Monroe 4 4 3 Czech Republic R Jebavý
Netherlands M Middelkoop 6 6
United States N Monroe 4 4 3 Czech Republic R Jebavý
Netherlands M Middelkoop 6 6
3
Czech Republic R Jebavý
Netherlands M Middelkoop 6 6 3 Czech Republic R Jebavý
Netherlands M Middelkoop 77 1 [10]
Netherlands M Middelkoop 6 6 3 Czech Republic R Jebavý
Netherlands M Middelkoop 77 1 [10]