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2018 Australian Open – Boys' doubles

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Boys' doubles
2018 Australian Open
Final
ChampionsFrance Hugo Gaston
France Clément Tabur
Runners-upGermany Rudolf Molleker
Germany Henri Squire
Score6–2, 6–2
Events
Singles men women boys girls
Doubles men women mixed boys girls
WC Singles men women quad
WC Doubles men women quad
Legends men women mixed
← 2017 · Australian Open · 2019 →
2018 tennis event results
Main article: 2018 Australian Open

Hugo Gaston and Clément Tabur won the boys' doubles tennis title at the 2018 Australian Open, defeating Rudolf Molleker and Henri Squire in the final, 6–2, 6–2.

Hsu Yu-hsiou and Zhao Lingxi were the defending champions, but Hsu was no longer eligible to participate in junior tournaments and Zhao chose not to participate.

Seeds

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1.   Argentina Sebastián Báez / Brazil Thiago Seyboth Wild (second round)
2.   United States Sebastian Korda / Colombia Nicolás Mejía (quarterfinals)
3.   Japan Naoki Tajima / Russia Alexey Zakharov (quarterfinals, withdrew)
4.   United Kingdom Aidan McHugh / Russia Timofey Skatov (quarterfinals)
5.   United States Tristan Boyer / Argentina Juan Manuel Cerúndolo (second round)
6.   Czech Republic Tomáš Macháč / Czech Republic Ondřej Štyler (semifinals)
7.   France Hugo Gaston / France Clément Tabur (champions)
8.   South Korea Jeong Yeong-seok / South Korea Park Ui-sung (withdrew)

Draw

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Key

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Finals

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Semifinals Final
                   

Top half

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First round Second round Quarterfinals Semifinals
WC Australia Campbell Salmon
Australia Stefan Storch 3 3 Uzbekistan S Fomin
United States J Lyeons 5 2
Italy Lorenzo Musetti
Italy Giulio Zeppieri 5 6 [7] WC Australia J Court
Australia A Crnokrak 4 3
WC Australia Jayden Court
Australia Alexander Crnokrak
7 4 [10] 3 Japan N Tajima
Russia A Zakharov

Bottom half

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First round Second round Quarterfinals Semifinals
Brazil Igor Gimenez
United States Sangeet Sridhar 6 3 [5] 6 Czech Republic T Macháč
Czech Republic O Štyler
6 7

References

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Australian Open boys' drawsheets
Singles
Doubles

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