2005 Stella Artois Championships – Doubles
From Wikipedia, the free encyclopedia
| Doubles | |
|---|---|
| 2005 Stella Artois Championships | |
| Final | |
| Champions | |
| Runners-up | |
| Score | 7–6(11–9), 7–6(7–4) |
| Details | |
| Draw | 24 |
| Events | |
2005 tennis event results
Main article: 2005 Stella Artois Championships
Bob Bryan and Mike Bryan were the defending champions and successfully defended their title, defeating Jonas Björkman and Max Mirnyi 7–6(11–9), 7–6(7–4) in the final.
Seeds
[edit ]All seeds receive a bye into the second round.
- Sweden Jonas Björkman / Belarus Max Mirnyi (final)
- United States Bob Bryan / United States Mike Bryan (champions)
- Zimbabwe Wayne Black / Zimbabwe Kevin Ullyett (second round)
- Australia Wayne Arthurs / Australia Paul Hanley (second round)
- Sweden Simon Aspelin / Australia Todd Perry (semifinals)
- Czech Republic František Čermák / Czech Republic Leoš Friedl (semifinals)
- Argentina Gastón Etlis / Argentina Martín Rodríguez (quarterfinals)
- United States Graydon Oliver / United States Jared Palmer (second round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
1
6
5
7
1
69
64
2
711
77
5
716
64
5
2
614
77
7
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
1
6
6
WC
4
6
6
WC
3
3
6
3
4
1
6
6
7
6
710
1
6
5
7
6
3
7
5
77
6
77
6
6
6
1
6
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
6
66
7
2
3
4
78
5
5
6
6
2
614
77
7
8
77
62
64
6
6
64
77
77
3
2
5
6
62
1
6
2
2
7
3
77
6
3
6
63
65
2
77
77