1997 Romanian Open – Singles
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Tennis tournament
| Singles | |
|---|---|
| 1997 Romanian Open | |
| Final | |
| Champion | Australia Richard Fromberg |
| Runner-up | Italy Andrea Gaudenzi |
| Score | 6–1, 7–6(7–2) |
| Details | |
| Draw | 32 (3WC/4Q/1LL) |
| Seeds | 8 |
| Events | |
1997 tennis event results
Main article: 1997 Romanian Open
Alberto Berasategui was the defending champion, but lost in the second round to Nicolás Lapentti.
Richard Fromberg won the title by defeating Andrea Gaudenzi 6–1, 7–6(7–2) in the final.[1]
Seeds
[edit ]- Spain Carlos Moyá (second round)
- Spain Àlex Corretja (second round)
- Spain Alberto Berasategui (second round)
- Spain Albert Portas (quarterfinals)
- Morocco Hicham Arazi (first round)
- Uruguay Marcelo Filippini (first round)
- Germany Marc-Kevin Goellner (semifinals)
- Morocco Karim Alami (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
7
Germany Marc-Kevin Goellner
2
64
Italy Andrea Gaudenzi
6
77
Italy Andrea Gaudenzi
1
62
Australia Richard Fromberg
4
6
6
Spain Francisco Clavet
6
3
4
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
6
Uruguay M Filippini
2
3
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
References
[edit ]- ^ "PLUS: TENNIS -- ROMANIAN OPEN; Fromberg Triumphs". The New York Times . Associated Press. 29 September 1997. Retrieved 13 February 2023.