1993 Dutch Open – Doubles
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| Doubles | |
|---|---|
| 1993 Dutch Open | |
| Final | |
| Champions | Netherlands Jacco Eltingh Netherlands Paul Haarhuis |
| Runners-up | Netherlands Hendrik Jan Davids Belgium Libor Pimek |
| Score | 4–6, 6–2, 7–5 |
| Events | |
1993 tennis event results
Main article: 1993 Dutch Open (tennis)
Paul Haarhuis and Mark Koevermans were the defending champions, but Koevermans did not compete this year.
Haarhuis teamed up with Jacco Eltingh and successfully defended his title, by defeating Hendrik Jan Davids and Libor Pimek 4–6, 6–2, 7–5 in the final.[1]
Seeds
[edit ]- Netherlands Jacco Eltingh / Netherlands Paul Haarhuis (champions)
- Spain Sergio Casal / Spain Emilio Sánchez (first round)
- Netherlands Tom Nijssen / Czech Republic Cyril Suk (semifinals)
- South Africa David Adams / Russia Andrei Olhovskiy (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
[edit ] First round
Quarterfinals
Semifinals
Final
References
[edit ]- ^ "Zelfs de robuuste Gustafsson kent grenzen" [Even the robust Gustafsson has limits]. NRC Handelsblad (in Dutch). 2 August 1993. Retrieved 6 April 2022.