1988 Rye Brook Open – Singles
From Wikipedia, the free encyclopedia
| Singles | |
|---|---|
| 1988 Rye Brook Open | |
| Final | |
| Champion | Czechoslovakia Milan Šrejber |
| Runner-up | India Ramesh Krishnan |
| Score | 6–2, 7–6 |
| Details | |
| Draw | 32 |
| Seeds | 8 |
| Events | |
← 1987 ·
Rye Brook Open
| |
1988 tennis event results
Main article: 1988 Rye Brook Open
Peter Lundgren was the defending champion, but did not participate this year.
Milan Šrejber won the title, defeating Ramesh Krishnan 6–2, 7–6 in the final.
Seeds
[edit ]- Netherlands Michiel Schapers (first round)
- India Ramesh Krishnan (final)
- West Germany Eric Jelen (first round)
- Czechoslovakia Milan Šrejber (champion)
- Argentina Horacio de la Peña (semifinals)
- Soviet Union Andrei Olhovskiy (second round)
- Sweden Christian Bergström (first round)
- Argentina Javier Frana (second round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
Italy Diego Nargiso
3
2
4
Czechoslovakia Milan Šrejber
6
6
4
Czechoslovakia Milan Šrejber
6
7
2
India Ramesh Krishnan
2
6
5
Argentina Horacio de la Peña
7
3
4
2
India Ramesh Krishnan
5
6
6
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
1
Netherlands M Schapers
5
6
6/WC
Soviet Union A Olhovskiy
7
6
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
5
Argentina H de la Peña
7
7
2
India R Krishnan
6
6