1969 New Zealand Open – Men's singles
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Main article: 1969 New Zealand Open
| Men's singles | |||||||
|---|---|---|---|---|---|---|---|
| 1969 New Zealand Open | |||||||
| Final | |||||||
| Champion | Australia Tony Roche [1] | ||||||
| Runner-up | Australia Rod Laver | ||||||
| Score | 6–1, 6–4, 4–6, 6–3 | ||||||
| Events | |||||||
| |||||||
1969 tennis event results
Tony Roche defeated Rod Laver 6–1, 6–4, 4–6, 6–3 to win the 1969 New Zealand Open singles event. Barry Phillips-Moore was the champion but did not defend his title.
Seeds
[edit ]Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.
- Australia Tony Roche (champion)
- Australia Rod Laver (final)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Quarterfinals
Semifinals
Final[1]
1
Australia Tony Roche
6
1
6
6
United Kingdom Roger Taylor
2
6
3
2
1
Australia Tony Roche
6
9
6
6
6
South Africa Raymond Moore
3
11
4
8
2
South Africa Raymond Moore
2
12
6
5
9
United States Pancho Gonzales
6
10
4
7
7
1
Australia Tony Roche
6
6
4
6
New Zealand Brian Fairlie
7
4
10
6
6
Australia John Newcombe
9
6
8
0
3
New Zealand Brian Fairlie
3
3
6
5
Soviet Union Toomas Leius
3
6
6
3
5
References
[edit ]- ^ a b "1969 Auckland – Singles draw". Association of Tennis Professionals (ATP).