1828 United States presidential election in Illinois
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Main article: 1828 United States presidential election
1828 United States presidential election in Illinois| Nominee | Andrew Jackson | John Quincy Adams |
|---|---|---|
| Party | Democratic | National Republican |
| Home state | Tennessee | Massachusetts |
| Running mate | John C. Calhoun | Richard Rush |
| Electoral vote | 3 | 0 |
| Popular vote | 9,560 | 4,662 |
| Percentage | 67.22% | 32.78% |
County Results
Jackson
50-60%
60-70%
70-80%
80-90%
90-100%
Adams
50-60%
60-70%
No Data/Vote
The 1828 United States presidential election in Illinois took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Illinois voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Illinois by a margin of 34.44%.
Results
[edit ]| 1828 United States presidential election in Illinois[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Andrew Jackson | 9,560 | 67.22% | 3 | |
| National Republican | John Quincy Adams (incumbent) | 4,662 | 32.78% | 0 | |
| Totals | 14,222 | 100.0% | 3 | ||
See also
[edit ]References
[edit ]- ^ "1828 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved February 28, 2013.
