1801 United States Senate election in Pennsylvania
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Not to be confused with 1801 United States Senate special election in Pennsylvania.
1801 U.S. Senate election in Pennsylvania102 Members of the Pennsylvania legislature
Plurality of votes needed to win
Nominee | Peter Muhlenberg | George Logan |
---|---|---|
Party | Democratic-Republican | Democratic-Republican |
Electoral vote | 46 | 45 |
Percentage | 45.10% | 44.12% |
Senator before election
Elected Senator
Elected Senator
The 1801 United States Senate election in Pennsylvania was held on February 19, 1801. Peter Muhlenberg was elected by the Pennsylvania General Assembly to the United States Senate.[1]
Results
[edit ]Incumbent Federalist William Bingham, who was elected in 1795, was not a candidate for re-election to another term. The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on February 19, 1801, to elect a new Senator to fill the term beginning on March 4, 1801. Two ballots were recorded. The results of the second and final ballot of both houses combined are as follows:
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic-Republican | Peter Muhlenberg | 46 | 45.10 | |
Democratic-Republican | George Logan | 45 | 44.12 | |
Not voting | 11 | 10.78 | ||
Total votes | 102 | 100 |
References
[edit ]- ^ a b "U.S. Senate Election - 19 February 1801" (PDF). Wilkes University. Retrieved September 28, 2013.