Defective matrix
In linear algebra, a defective matrix is a square matrix that does not have a complete basis of eigenvectors, and is therefore not diagonalizable. In particular, an {\displaystyle n\times n} matrix is defective if and only if it does not have {\displaystyle n} linearly independent eigenvectors.[1] A complete basis is formed by augmenting the eigenvectors with generalized eigenvectors, which are necessary for solving defective systems of ordinary differential equations and other problems.
An {\displaystyle n\times n} defective matrix always has fewer than {\displaystyle n} distinct eigenvalues, since distinct eigenvalues always have linearly independent eigenvectors. In particular, a defective matrix has one or more eigenvalues {\displaystyle \lambda } with algebraic multiplicity {\displaystyle m>1} (that is, they are multiple roots of the characteristic polynomial), but fewer than {\displaystyle m} linearly independent eigenvectors associated with {\displaystyle \lambda }. If the algebraic multiplicity of {\displaystyle \lambda } exceeds its geometric multiplicity (that is, the number of linearly independent eigenvectors associated with {\displaystyle \lambda }), then {\displaystyle \lambda } is said to be a defective eigenvalue.[1] However, every eigenvalue with algebraic multiplicity {\displaystyle m} always has {\displaystyle m} linearly independent generalized eigenvectors.
A real symmetric matrix and more generally a Hermitian matrix, and a unitary matrix, is never defective; more generally, a normal matrix (which includes Hermitian and unitary matrices as special cases) is never defective.
Jordan block
[edit ]Any nontrivial Jordan block of size {\displaystyle 2\times 2} or larger (that is, not completely diagonal) is defective. (A diagonal matrix is a special case of the Jordan normal form with all trivial Jordan blocks of size {\displaystyle 1\times 1} and is not defective.) For example, the {\displaystyle n\times n} Jordan block
- {\displaystyle J={\begin{bmatrix}\lambda &1&\;&\;\\\;&\lambda &\ddots &\;\\\;&\;&\ddots &1\\\;&\;&\;&\lambda \end{bmatrix}},}
has an eigenvalue, {\displaystyle \lambda } with algebraic multiplicity {\displaystyle n} (or greater if there are other Jordan blocks with the same eigenvalue), but only one distinct eigenvector {\displaystyle Jv_{1}=\lambda v_{1}}, where {\displaystyle v_{1}={\begin{bmatrix}1\0円\\\vdots \0円\end{bmatrix}}.} The other canonical basis vectors {\displaystyle v_{2}={\begin{bmatrix}0\1円\\\vdots \0円\end{bmatrix}},~\ldots ,~v_{n}={\begin{bmatrix}0\0円\\\vdots \1円\end{bmatrix}}} form a chain of generalized eigenvectors such that {\displaystyle Jv_{k}=\lambda v_{k}+v_{k-1}} for {\displaystyle k=2,\ldots ,n}.
Any defective matrix has a nontrivial Jordan normal form, which is as close as one can come to diagonalization of such a matrix.
Example
[edit ]A simple example of a defective matrix is
- {\displaystyle {\begin{bmatrix}3&1\0円&3\end{bmatrix}},}
which has a double eigenvalue of 3 but only one distinct eigenvector
- {\displaystyle {\begin{bmatrix}1\0円\end{bmatrix}}}
(and constant multiples thereof).
See also
[edit ]- Jordan normal form – Form of a matrix indicating its eigenvalues and their algebraic multiplicities
Notes
[edit ]- ^ a b Golub & Van Loan (1996, p. 316)
References
[edit ]- Golub, Gene H.; Van Loan, Charles F. (1996), Matrix Computations (3rd ed.), Baltimore: Johns Hopkins University Press, ISBN 978-0-8018-5414-9
- Strang, Gilbert (1988). Linear Algebra and Its Applications (3rd ed.). San Diego: Harcourt. ISBN 978-970-686-609-7.