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std::make_any

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< cpp‎ | utility‎ | any
 
 
Utilities library
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Relational operators (deprecated in C++20)
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Defined in header <any>
template< class T, class... Args >
std::any make_any( Args&&... args );
(1) (since C++17)
template< class T, class U, class... Args >
std::any make_any( std::initializer_list <U> il, Args&&... args );
(2) (since C++17)

Constructs an any object containing an object of type T, passing the provided arguments to T's constructor.

1) Equivalent to return std::any (std::in_place_type <T>, std::forward <Args>(args)...);
2) Equivalent to return std::any (std::in_place_type <T>, il, std::forward <Args>(args)...);

[edit] Example

Run this code
#include <any>
#include <complex>
#include <functional>
#include <iostream>
#include <string>
 
int main()
{
 auto a0 = std::make_any<std::string >("Hello, std::any!\n");
 auto a1 = std::make_any<std::complex <double>>(0.1, 2.3);
 
 std::cout << std::any_cast <std::string &>(a0);
 std::cout << std::any_cast <std::complex <double>&>(a1) << '\n';
 
 using lambda = std::function <void(void)>;
 
 // Put a lambda into std::any. Attempt #1 (failed).
 std::any a2 = [] { std::cout << "Lambda #1.\n"; };
 std::cout << "a2.type() = \"" << a2.type().name() << "\"\n";
 
 // any_cast casts to <void(void)> but actual type is not
 // a std::function..., but ~ main::{lambda()#1}, and it is
 // unique for each lambda. So, this throws...
 try
 {
 std::any_cast <lambda>(a2)();
 }
 catch (std::bad_any_cast const& ex)
 {
 std::cout << ex.what() << '\n';
 }
 
 // Put a lambda into std::any. Attempt #2 (successful).
 auto a3 = std::make_any<lambda>([] { std::cout << "Lambda #2.\n"; });
 std::cout << "a3.type() = \"" << a3.type().name() << "\"\n";
 std::any_cast <lambda>(a3)();
}

Possible output:

Hello, std::any!
(0.1,2.3)
a2.type() = "Z4mainEUlvE_"
bad any_cast
a3.type() = "St8functionIFvvEE"
Lambda #2.

[edit] See also

constructs an any object
(public member function) [edit]
(C++17)
type-safe access to the contained object
(function template) [edit]
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