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std::ranges::destroy

From cppreference.com
< cpp‎ | memory
 
 
Memory management library
(exposition only*)
Uninitialized storage (until C++20)
(until C++20*)
(until C++20*)

(C++11)(until C++23)
(C++11)(until C++23)
(C++11)(until C++23)
(C++11)(until C++23)
(C++11)(until C++23)
(C++11)(until C++23)
 
Defined in header <memory>
Call signature
template< no-throw-input-iterator I, no-throw-sentinel-for<I> S >

    requires std::destructible <std::iter_value_t <I>>

constexpr I destroy( I first, S last ) noexcept;
(1) (since C++20)
template< no-throw-input-range R >

    requires std::destructible <ranges::range_value_t <R>>

constexpr ranges::borrowed_iterator_t <R> destroy( R&& r ) noexcept;
(2) (since C++20)
1) Destroys the objects in the range [firstlast), as if by
for (; first != last; ++first)
 std::ranges::destroy_at (std::addressof (*first));
return first;
2) Same as (1), but uses r as the source range, as if using ranges::begin (r) as first and ranges::end (r) as last.

The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:

[edit] Parameters

first, last - the iterator-sentinel pair defining the range of elements to destroy
r - the range to destroy

[edit] Return value

An iterator compares equal to last.

[edit] Complexity

Linear in the distance between first and last.

[edit] Possible implementation

struct destroy_fn
{
 template<no-throw-input-iterator I, no-throw-sentinel-for<I> S>
 requires std::destructible <std::iter_value_t <I>>
 constexpr I operator()(I first, S last) const noexcept
 {
 for (; first != last; ++first)
 std::ranges::destroy_at (std::addressof (*first));
 return first;
 }
 
 template<no-throw-input-range R>
 requires std::destructible <std::ranges::range_value_t <R>>
 constexpr std::ranges::borrowed_iterator_t <R> operator()(R&& r) const noexcept
 {
 return operator()(std::ranges::begin (r), std::ranges::end (r));
 }
};
 
inline constexpr destroy_fn destroy{};

[edit] Example

The following example demonstrates how to use ranges::destroy to destroy a contiguous sequence of elements.

Run this code
#include <iostream>
#include <memory>
#include <new>
 
struct Tracer
{
 int value;
 ~Tracer() { std::cout << value << " destructed\n"; }
};
 
int main()
{
 alignas(Tracer) unsigned char buffer[sizeof(Tracer) * 8];
 
 for (int i = 0; i != 8; ++i)
 new(buffer + sizeof(Tracer) * i) Tracer{i}; // manually construct objects
 
 auto ptr = std::launder (reinterpret_cast<Tracer*>(buffer));
 
 std::ranges::destroy(ptr, ptr + 8);
}

Output:

0 destructed
1 destructed
2 destructed
3 destructed
4 destructed
5 destructed
6 destructed
7 destructed

[edit] See also

destroys a number of objects in a range
(algorithm function object)[edit]
destroys an object at a given address
(algorithm function object)[edit]
(C++17)
destroys a range of objects
(function template) [edit]
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