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std::array<T,N>::operator[]

From cppreference.com
< cpp‎ | container‎ | array
 
 
 
 
reference operator[]( size_type pos );
(1) (since C++11)
(constexpr since C++17)
const_reference operator[]( size_type pos ) const;
(2) (since C++11)
(constexpr since C++14)

Returns a reference to the element at specified location pos.

If pos < size() is false, the behavior is undefined.

(until C++26)

If pos < size() is false:

  • If the implementation is hardened, a contract violation occurs. Moreover, if the contract-violation handler returns under "observe" evaluation semantic, the behavior is undefined.
  • If the implementation is not hardened, the behavior is undefined.
(since C++26)

[edit] Parameters

pos - position of the element to return

[edit] Return value

Reference to the requested element.

[edit] Complexity

Constant.

[edit] Notes

Unlike std::map::operator[] , this operator never inserts a new element into the container. Accessing a nonexistent element through this operator is undefined behavior, unless the implementation is hardened(since C++26).

[edit] Example

The following code uses operator[] to read from and write to a std::array <int, N>:

Run this code
#include <array>
#include <iostream>
 
int main()
{
 std::array <int, 4> numbers{2, 4, 6, 8};
 
 std::cout << "Second element: " << numbers[1] << '\n';
 
 numbers[0] = 5;
 
 std::cout << "All numbers:";
 for (auto i : numbers)
 std::cout << ' ' << i;
 std::cout << '\n';
}

Output:

Second element: 4
All numbers: 5 4 6 8

[edit] See also

access specified element with bounds checking
(public member function) [edit]
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