std::chrono::duration<Rep,Period>::operator+=, -=, *=, /=, %=
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std::chrono::duration
Member functions
duration::operator+=duration::operator-=duration::operator*=duration::operator/=duration::operator%=
Non-member functions
(until C++20)(C++20)
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Helper classes
(1)
duration& operator+=( const duration& d );
(since C++11) (constexpr since C++17)
(2)
duration& operator-=( const duration& d );
(since C++11) (constexpr since C++17)
(3)
duration& operator*=( const rep& rhs );
(since C++11) (constexpr since C++17)
(4)
duration& operator/=( const rep& rhs );
(since C++11) (constexpr since C++17)
(5)
duration& operator%=( const rep& rhs );
(since C++11) (constexpr since C++17)
(6)
duration& operator%=( const duration& rhs );
(since C++11) (constexpr since C++17)
Performs compound assignments between two durations with the same period or between a duration and a tick count value.
If rep_ is the member variable holding the number of ticks in this duration object,
1) Equivalent to rep_ += d.count(); return *this;.
2) Equivalent to rep_ -= d.count(); return *this;.
3) Equivalent to rep_ *= rhs; return *this;.
4) Equivalent to rep_ /= rhs; return *this;.
5) Equivalent to rep_ %= rhs; return *this;.
6) Equivalent to rep_ %= d.count(); return *this;.
Contents
[edit] Parameters
d
-
duration on the right-hand side of the operator
rhs
-
number of ticks on the right-hand side of the operator
[edit] Return value
A reference to this duration after modification.
[edit] Example
Run this code
#include <chrono> #include <iostream> int main() { std::chrono::minutes m(11); m *= 2; m += std::chrono::hours (10); // hours implicitly convert to minutes std::cout << m.count() << " minutes equals " << std::chrono::duration_cast <std::chrono::hours >(m).count() << " hours and "; m %= std::chrono::hours (1); std::cout << m.count() << " minutes\n"; }
Output:
622 minutes equals 10 hours and 22 minutes