I plan to determine the open/close loop transfer function of the attached motor. I have been able to combine K(s) to 1/s in series but am not too sure of how to add up 12/pi outside the summing junction and what to use as the gain(either tetha 0/teta 1 or teta 0/V1(s).
Also how to use this to determine the closed loop of the system enter image description here
3 Answers 3
Start by putting some equations on it: -
schematic
simulate this circuit – Schematic created using CircuitLab
The output of A is called Vout, but clearly ....
\$V_{out} = A(V_{in} - B\cdot V_{out})\$
This boils down to \$\dfrac{V_{out}}{V_{in}} = \dfrac{A}{1+AB} \$
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\$\begingroup\$ Thanks Andy, In finding the forward path for the open loop I have added 12/pi that is not in the feedback path. does that look ok. \$\endgroup\$Shittu Olalekan– Shittu Olalekan2015年12月23日 21:36:47 +00:00Commented Dec 23, 2015 at 21:36
1.) Together with the first block (12/Pi) and Andy aka`s answer you will be able to find the closed-loop transfer function.
2.) The open-loop function is the product of all forward blocks (without the feedback path). This expression should not be confused with the "loop gain" which is simply the product A*B (using Andy aka`s notation)-
3.) The full closed-loop gain is defined as the ratio of two angles (tetha,0/teta,i).
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\$\begingroup\$ LvW, Going by your second comment, for the open loop transfer function, all the forward function including 12/pi with input(teta i) & output(Vi(s)). Thats what I've done before posting the diagram. \$\endgroup\$Shittu Olalekan– Shittu Olalekan2015年12月23日 21:31:08 +00:00Commented Dec 23, 2015 at 21:31
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\$\begingroup\$ Whats a unity negative feedback? \$\endgroup\$Shittu Olalekan– Shittu Olalekan2015年12月23日 21:51:18 +00:00Commented Dec 23, 2015 at 21:51
The relation between open loop F(s) and closed loop H(s) is H(s)=F(s)/1+F(s) if and only if the feedback is 1. In your case the feedbak is 12/pi, but also the setpoint is multiplied with same, so the solution of your homework is: - find how to move the feedback into the loop and make feedback =1, then some coeficient will cancell out and use the formula openv vs. closed loop with fbck=1
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\$\begingroup\$ Quote: "....find how to move the feedback into the loop and make feedback =1"...My comment: For which purpose such an unnecessary procedure? \$\endgroup\$LvW– LvW2015年12月24日 08:36:16 +00:00Commented Dec 24, 2015 at 8:36
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\$\begingroup\$ @LvW Because this is a classic exercise at univeristy, and two same gains 12/pi are pointing that professor wants exactly that thing. \$\endgroup\$Marko Buršič– Marko Buršič2015年12月24日 17:14:42 +00:00Commented Dec 24, 2015 at 17:14
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\$\begingroup\$ Ahhh - yes, this could be the case. \$\endgroup\$LvW– LvW2015年12月25日 08:25:14 +00:00Commented Dec 25, 2015 at 8:25