I have a script for school that mimics the cp command. Part of the assignment is to modify the script so that the while
loop (that assigns stdin
to the variable filelist
) is instead done with sed.
The last argument needs to be saved to the variable to
because that could be a directory depending on other user input in the script.
while [ "$#" -gt 1 ]
do
filelist="$filelist 1ドル"
shift
done
to="1ドル"
Is this finished product good? How could I polish it up?
filelist=$(echo $* | sed 's/ [^ ]*$//')
to=$(echo $* | sed 's/^.* \([^ ]*\)$/1円/')
1 Answer 1
filelist="$(
IFS='
'
echo "$*" | sed -n '$!H;${x;s/.//;s/\n/ /g;p;}'
)"
to="$(
IFS='
'
echo "$*" | sed '$!d'
)"
This should do, assuming there are no new lines in the parameter/s.
Your code assume there is only 1 word per argument. This have nearly no impact unless the last argument is a multi word (miss interpreted by your code taking the very last word and not argument).
For this reason:
- Use another separator than standard white space/tab for passing the parameter to sed.
- Use
$*
(and not$@
) to have the shell separation on argument and not word. - Using IFS Internal Field Separator of the shell.
- Using a sub shell to limit IFS scope to this function (hopefully already the case with
"$(...)"
used for assignation.
- Use
- Adapt sed to separate argument with new line, and readapt the new line to white space for final value (sed by default work per line so need to load the lines in buffer before working on it at the end).
-
\$\begingroup\$ sorry missing this part, i will adapt the post \$\endgroup\$NeronLeVelu– NeronLeVelu2015年07月28日 07:06:51 +00:00Commented Jul 28, 2015 at 7:06
while
loop produces different output, " 1 2 3" vs. "1 2 3" by thesed
call. \$\endgroup\$to
assignment.len=$#; to=${!len}
orlen=$#; a=("$@"); to=${a[$# - 1]}
. \$\endgroup\$