JavaScript object to JSON

Question

Since I didn't find a way to properly transform JavaScript object to JSON with PHP, I wrote a snippet.

---

Lets assume the following excerpt from Google Fonts JavaScript API:

WebFontConfig = {
 google: { families: [ 'Source+Sans+Pro:300,400,600,700,300italic,400italic,600italic,700italic:latin,latin-ext' ] }
};

This, given straight to PHP's json_decode will null out and JSONLint will say it's invalid.

Since I need this data in JSON after the template has been parsed (working on an exporter), I wrote this snippet (which double-quotes the hell out of this one):

// gather WebFontConfig arrays
$webfonts = preg_match_all('/(WebFontConfig\s*?=\s*?)\{(.+?)(\};)/s', $scriptData, $fontdata, PREG_SET_ORDER);
// kids, dont do this at home
foreach ($fontdata as $founddata)
{
 $original = $founddata[0];
 $WFCVariable = $founddata[1];
 // leave outer braces only
 $usable = str_replace($WFCVariable, '', $original);
 $usable = trim($usable, ';');
 // transform keys into double-quoted keys
 $usable = preg_replace('/(\w+)(:\s*?)(\{|\[)/im', '"1ドル"2ドル3ドル', $usable);
 // prepare to transform array wrapping single quotes to double quotes
 $lookups = array(
 '/(\[)(\s*?)(\')/',
 '/(\')(\s*?)(\])/'
 );
 $replace = array(
 '1ドル2ドル"',
 '"2ドル3ドル'
 );
 $usable = preg_replace($lookups, $replace, $usable);
 // decode
 $jsoned = json_decode($usable);
 // and check
 var_dump($jsoned);
}

$scriptData essentially is the above JavaScript object trim-extracted out of my template through DOMDocument .. DOMNode->nodeValue.

---

There is no problem with the snippet, it converts my data into PHP array without problems.

My concern, though, is, whether this is the most optimal way of doing it?

• Paul S.: possible duplicate of Parsing Javascript (not JSON) in PHP
• rlemon: I'm wondering why you don't just call their (Google Web Fonts) JSON api from the server?. It will return the results properly formatted for you. You do need an API key, however those are easily obtained.
• tomsseisums: @rlemon, oh, didn't see that GWF has it. Will look into it.

Answer 1

As this works for you and as there is no javascript interpreter in PHP unless you install it (there is a V8 PHP extension IIRC), I would say you did this right so far.

Which else criteria could there be than your own ones? You should probably write unit and acceptance tests for it. And remove the var_dump debug cruft out of it. But by the way you do this on it's own, it does not look too far off.