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I'm trying to devise a tkinter gui, that, among others, lets users choose a 'working folder' and a 'destination folder (and there is more coming). I stripped the code to its bare functionality hereunder.

I found myself duplicating code for the selection of both the 'working folder' and the 'destination' folder. I came up with the solution to put these variables in a dictionary (I could pass them as mutable objects along with the lambda). Although it is a working solution, I have the feeling there is more standard way of achieving this objective.

My question therefore is: how can I make my _browsefile() function work whilst changing the value of self.working_dir and self.destination_dir, without using an artificial dictionary structure, hence avoiding duplicate code? This would implicate that I can generalize the _browsefile func somehow.

I have seen very advanced reusage features in text books, but currently this is out of my league. If I can learn to tackle this 'easy' one, it would possibly help me on my journey.

Thank you for giving me advice in doing it the Pythonic way...

import tkinter as tk
from tkinter import filedialog
class View():
 def __init__(self, parent):
 self.parent = parent
 
 self.gui_variables = {'working dir': '',
 'destination dir': ''}
 
 self.menu()
 
 def menu(self):
 self.folder_button1 = tk.Button(self.parent, text="Choose Working Folder",
 command=lambda: self._browsefile(self.gui_variables['working dir']))
 self.folder_button1.pack()
 self.folder_button2 = tk.Button(self.parent, text="Choose Dest. Folder",
 command=lambda: self._browsefile(self.gui_variables['destination dir']))
 self.folder_button2.pack()
 def _browsefile(self, directory):
 answer = tk.filedialog.askdirectory()
 self.gui_variables[directory] = answer
if __name__ == '__main__':
 root = tk.Tk()
 View(root)
 root.mainloop()
Reinderien
70.9k5 gold badges76 silver badges256 bronze badges
asked Jan 28, 2021 at 22:01
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1 Answer 1

1
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Don't use a dictionary. You can just refer to the attrs of a class by their name. Something like:

import tkinter as tk
from tkinter import filedialog
from typing import Optional
class View:
 def __init__(self, parent: tk.Tk):
 self.parent = parent
 self.working_dir: Optional[str] = None
 self.dest_dir: Optional[str] = None
 self.menu('Working', 'working_dir')
 self.menu('Dest.', 'dest_dir')
 def menu(self, title: str, attr: str):
 def browse():
 setattr(self, attr, tk.filedialog.askdirectory())
 button = tk.Button(
 self.parent,
 text=f'Choose {title} Folder',
 command=browse,
 )
 button.pack()
if __name__ == '__main__':
 root = tk.Tk()
 View(root)
 root.mainloop()

Notes:

  • Do not add a () suffix to your class
  • Do not assign those buttons as members on your class
  • Centralize the creation of the buttons and the associated command
  • For the command handler, use a simple closure
  • To target a specific member variable, accept a parameter that's used with setattr
  • Use type hints
answered Jan 29, 2021 at 4:50
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3
  • \$\begingroup\$ Thank you for reviewing my code and for the additional advice. \$\endgroup\$ Commented Jan 29, 2021 at 10:40
  • \$\begingroup\$ What's wrong with using () ? \$\endgroup\$ Commented Feb 1, 2021 at 22:36
  • 1
    \$\begingroup\$ @CoolCloud it's a Python 2 construct, not needed these days \$\endgroup\$ Commented Feb 1, 2021 at 23:38

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