I've wrote a C++ program to calculate the determinant of a matrix:
#include <iostream>
#include <string>
double getDeterminant(double arr[], int dimension);
int main() {
//First, the user has to enter the dimension of the matrix
int dimension;
std::cout << "Please enter dimension of Matrix: ";
std::cin >> dimension;
std::cout << std::endl;
double matrix[dimension][dimension];
//Now, the user has to enter the matrix line by line, seperated by commas
std::string str;
for(int i = 1; i <= dimension; i++) {
std::cout << "Enter line " << i << " only seperated by commas: ";
std::cin >> str;
std::cout << std::endl;
str = str + ',';
std::string number;
int count = 0;
for(int k = 0; k < str.length(); k++) {
if(str[k] != ',') {
number = number + str[k];
}
else {
matrix[i - 1][count] = std::stod(number);
number = "";
count++;
}
}
}
//Conversion to a onedimensional matrix to be able to give it over as a parameter
double array[dimension * dimension];
int k = 0;
for(int i = 0; i < dimension; i++) {
for(int j = 0; j < dimension; j++) {
array[k] = matrix[i][j];
k++;
}
}
//Output
for(int i = 0; i < dimension; i++) {
for(int j = 0; j < dimension; j++) {
std::cout << matrix[i][j] << " ";
}
std::cout << std::endl;
}
std::cout << "Determinant of the matrix is : " << getDeterminant(array, dimension) << std::endl;
return 0;
}
double getDeterminant(double array[], int dimension) {
//Formula for 2x2-matrix
if(dimension == 2) {
return array[0] * array[3] - array[1] * array[2];
}
//Conversion back to 2D-array
double matrix[dimension][dimension];
int k = 0;
for(int i = 0; i < dimension; i++) {
for(int j = 0; j < dimension; j++) {
matrix[i][j] = array[k];
k++;
}
}
double result = 0;
int sign = 1;
for(int i = 0; i < dimension; i++) {
//Submatrix
double subMatrix[dimension - 1][dimension -1];
for(int m = 1; m < dimension; m++) {
int z = 0;
for(int n = 0; n < dimension; n++) {
if(n != i) {
subMatrix[m-1][z] = matrix[m][n];
z++;
}
}
}
//Conversion of the submatrix to 1D-array
double array2[(dimension - 1) * (dimension - 1)];
int k = 0;
for(int x = 0; x < dimension - 1; x++) {
for(int y = 0; y < dimension - 1; y++) {
array2[k] = subMatrix[x][y];
k++;
}
}
//recursive call
result = result + sign * matrix[0][i] * getDeterminant(array2, dimension -1);
sign = -sign;
}
return result;
}
I would appreciate any suggestions on improving the code!
You can find the follow-up question here.
1 Answer 1
double matrix[dimension][dimension];
double array[dimension * dimension];
double matrix[dimension][dimension];
double subMatrix[dimension - 1][dimension -1];
double array2[(dimension - 1) * (dimension - 1)];
None of those are legal C++, because dimension
isn't a constant-expression.
We have a signed/unsigned comparison here:
for(int k = 0; k < str.length(); k++) {
We can easily eliminate the compiler warning by using a more appropriate type:
for (std::size_t k = 0; k < str.length(); ++k) {
But a better fix, given we only use k
to index str
, is to use a range-based loop:
for (auto const c: str) {
When using operator>>
on a stream, we must always check that it succeeded, before we depend on the result:
std::size_t dimension;
std::cin >> dimension;
if (!std::cin) {
std::cerr << "Input failed\n";
return EXIT_FAILURE; // needs <cstdlib>
}
if (dimension == 0) {
std::cout << "1\n"; // empty matrix determinant
}
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\$\begingroup\$ Should I use vectors instead? \$\endgroup\$user214772– user2147722020年02月10日 10:15:20 +00:00Commented Feb 10, 2020 at 10:15
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\$\begingroup\$ That would be a good choice, as that handles memory management etc. Do note that vector-of-vector doesn't have the good locality properties of array-of-array, so consider using or making a matrix class that's more efficient. You could use OpenCV
cv::Mat
, or look at the Matrix class I recently reviewed. \$\endgroup\$Toby Speight– Toby Speight2020年02月10日 10:26:08 +00:00Commented Feb 10, 2020 at 10:26 -
\$\begingroup\$ I would use
const auto&
in the range-for
loop, not that the type of a string will ever change. \$\endgroup\$S.S. Anne– S.S. Anne2020年02月10日 12:20:36 +00:00Commented Feb 10, 2020 at 12:20 -
\$\begingroup\$ "empty matrix has zero determinant" – Actually not: codereview.stackexchange.com/a/236988/35991 :) \$\endgroup\$Martin R– Martin R2020年02月10日 12:53:05 +00:00Commented Feb 10, 2020 at 12:53
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1\$\begingroup\$ @S.S.Anne, that might make sense (I'm guessing that most compilers are smart enough to copy characters rather than blindly using references as coded). \$\endgroup\$Toby Speight– Toby Speight2020年02月10日 13:23:39 +00:00Commented Feb 10, 2020 at 13:23