I have made a function which calculates the index of a point to which an arbitrary point on a polygon made of XY points belong.
This is a visual representation:
enter image description here
And this is the function I made:
stock GetNodeIndexFromPolygonIndex(polygonid,Polygon_Size)
{
new polid = (polygonid - (polygonid % 2));
new mid = Polygon_Size/2;
if(polid > mid)
{
polid /= 2;
return (mid - (++polid));
}
else
{
polid /= 2;
if(polid == 0)
{
return 0;
}
return --polid;
}
}
Is there anything I can optimize here? This function is going to be called ~2000 times in the worst case in one run on a single threaded application. I would like this to be as optimal as possible. Is it already?
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2\$\begingroup\$ I personally don't understand the explanation. Why 3 in the first red circle for example? \$\endgroup\$Quentin Pradet– Quentin Pradet2013年02月07日 14:32:47 +00:00Commented Feb 7, 2013 at 14:32
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\$\begingroup\$ The basic thing is thhat the red circles are a PATH which is created from XYZ points and have indexes from 0 to up. yet, there is a polygon around it which has to be closed so one polygon point has 4 indexes (XY, XY, first and last polygon point). The black points are thus the polygon around the red path with a specific width. Just like here: i.sstatic.net/x865n.png \$\endgroup\$user19795– user197952013年02月07日 16:15:52 +00:00Commented Feb 7, 2013 at 16:15
1 Answer 1
First, I do not know anything about PAWN.
Does it have a profiler? Can any profiler be used? If yes, probably use it.
If no, write at least some test units to measure execution time.
I will assume typical language elements. I will assume polygonid > 0
and Polygon_Size > 0
, because I do not know (and did not find in short time) the behavior of /
and %
for negative numbers.
As far as I understood, there is a virtual machine between compiler and execution. This makes things a little bit more complex, but well, we will assume that nothing special happens there.
Some of the optimizations could change nothing, because the compiler already does it. I can not predict or test it.
That said, I will choose line after line. I do not know if you can change the algorithm, because like Cygal I do not understand the exact purpose.
new polid = (polygonid - (polygonid % 2));
This makes polid the next smallest even number? %
is rather costly, you could either do a polygonid & 1
instead of polygonid % 2
or new polid = polygonid & (max_value - 1)
which will set all bits, but the last one to zero. max_value - 1 should be precalculated.
new mid = Polygon_Size/2;
Change to: new mid = Polygon_Size >> 1
This will be done most probably by the compiler anyway, but we do not know, so lets try it.
polid /= 2;
This is calculated in both branches. It could help to do it before the branching:
new polid_half = polid >> 1;
...
return (mid - (++polid));
This depends on the language details. It could be that ++polid
as preincrement operator will load polid, update it by one, and store polid back. We do not plan to use the modified polid, so we could try return (mid - polid + 1)
assuming that ++polid
is not some magic fast special instruction compared to the normal +
.
if(polid == 0)
{
return 0;
}
This does only happen if polygonid is 0 or 1. If this happens a lot, you should return immediately at the beginning, saving all the rest:
if (polygonid < 2 ) //assuming polygonid > 0
return 0;
And remove the check inside the else branch.
return --polid;
Same as before, it could be better to return polid - 1
Depending on the branch prediction handling, it could be better to have only one return point, not one in every branch. You could introduce a return value and set it according to the current logic.
I would try one change after the next and profile every step. All together, it could be:
stock GetNodeIndexFromPolygonIndex(polygonid,Polygon_Size)
{
if (polygonid < 2 ) //assuming polygonid > 0
return 0;
new result = 0;
new polid = polygonid & (max_value - 1); //polid is a bad name
new polid_half = polid >> 1;
new mid = Polygon_Size >> 1;
if(polid > mid)
result = mid - polid_half + 1;
else
result = polid_half - 1;
return result;
}
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\$\begingroup\$ Another caveat: those micro-optimizations make the code way less readable, but since it's probably the only thing to do, here's an upvote for you. :) \$\endgroup\$Quentin Pradet– Quentin Pradet2013年02月08日 08:28:29 +00:00Commented Feb 8, 2013 at 8:28
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\$\begingroup\$ @Cygal Well, the
>> 1
are probably too much and someif-else
braces would also increase readability. \$\endgroup\$Sulthan– Sulthan2013年02月08日 13:55:46 +00:00Commented Feb 8, 2013 at 13:55