6
\$\begingroup\$

I have this very simple template:

#include <algorithm>
#include <initializer_list>
#include <iostream>
#include <iterator>
#include <list>
#include <set>
#include <vector>
template<class Container>
class ImmutableContainerView {
private:
 Container& my_container;
public:
 ImmutableContainerView(Container& container) :
 my_container {container} {}
 typename Container::const_iterator cbegin() const {
 return my_container.cbegin();
 }
 typename Container::const_iterator cend() const {
 return my_container.cend();
 }
 typename Container::const_reverse_iterator crbegin() const {
 return my_container.crbegin();
 }
 typename Container::const_reverse_iterator crend() const {
 return my_container.crend();
 }
 typename Container::size_type size() const {
 return my_container.size();
 }
 bool empty() const {
 return my_container.empty();
 }
};
int main(int argc, const char * argv[]) {
 std::initializer_list<int> il = { 1, 2, 4, 5, 6 };
 std::list<int> my_list = il;
 std::set<int> my_set = il;
 std::vector<int> my_vector = il;
 ImmutableContainerView<std::list<int>> my_immutable_list(my_list);
 ImmutableContainerView<std::set<int>> my_immutable_set(my_set);
 ImmutableContainerView<std::vector<int>> my_immutable_vector(my_vector);
 // Iterators:
 std::ostream_iterator<int> out_it (std::cout, ", ");
 std::copy(my_immutable_list.cbegin(), my_immutable_list.cend(), out_it);
 std::cout << "\n";
 std::copy(my_immutable_set.cbegin(), my_immutable_set.cend(), out_it);
 std::cout << "\n";
 std::copy(my_immutable_vector.cbegin(), my_immutable_vector.cend(), out_it);
 std::cout << "\n";
 // Reversed iterators:
 std::copy(my_immutable_list.crbegin(), my_immutable_list.crend(), out_it);
 std::cout << "\n";
 std::copy(my_immutable_set.crbegin(), my_immutable_set.crend(), out_it);
 std::cout << "\n";
 std::copy(my_immutable_vector.crbegin(), my_immutable_vector.crend(), out_it);
 std::cout << "\n";
 // Size:
 std::cout << my_immutable_list.size() << "\n";
 std::cout << my_immutable_set.size() << "\n";
 std::cout << my_immutable_vector.size() << "\n";
 // Empty:
 std::cout << std::boolalpha;
 std::cout << my_immutable_list.empty() << "\n";
 std::cout << my_immutable_set.empty() << "\n";
 std::cout << my_immutable_vector.empty() << "\n";
 return 0;
}

I would like to hear comments on how to improve it. In particular, is it possible to do some metaprogramming trickery such that it can adapt to different containers; for example, it could provide operator[size_t] for std::vector, but find for std::set?

asked Jul 4, 2017 at 17:59
\$\endgroup\$

1 Answer 1

9
\$\begingroup\$

Your view isn't immutable, though immutability might be a property of the underlying object. It's a constant view, meaning the underlying object might change, but not from that view. The canonical way to get a constant view is by the way to use a constant reference, unless the view should erase some of the differences between underlying containers, like std::string_view does.


You are missing .begin(), .end(), .rbegin() and .rend().

Your view is constant, fine, but forcing everyone to explicitly say so for each function-call breaks interface conventions.

The missing functions are the common interface, the ones you provided just optional convenience-functions for calling manually which might not be provided even if possible, and certainly never used in generic code. Take a look at <iterator> and the free functions for accessing any generic range there.

answered Jul 4, 2017 at 20:12
\$\endgroup\$

Your Answer

Draft saved
Draft discarded

Sign up or log in

Sign up using Google
Sign up using Email and Password

Post as a guest

Required, but never shown

Post as a guest

Required, but never shown

By clicking "Post Your Answer", you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.