Decide if a number is even or odd by using bitwise operator

Question

The following exercise is from an Assembler-course I'm taking:

Write a program that takes a number x as input, and returns:

• 0 if x is even.
• 1 if x is odd.

Full exercise-page here: GitHub

Here's my solution:

format PE console
entry start
include 'win32a.inc' 
; ===============================================
section '.text' code readable executable
start:
 call read_hex ; Provided by the teacher. Reads a hexadecimal number from stdin.
 and eax, 0x1
 cmp eax, 0x0 
 je print_result
 mov eax, 0x1
print_result:
 call print_eax_binary ; Provided by the teacher. Prints a binary number to stdout.
 ; Exit the process:
 push 0
 call [ExitProcess]
include 'training.inc'

I would say it works alright:

enter image description here

• Is my solution valid?
• Can it be improved? Respectively, is there a better solution possible?

Answer 1

Here are some things that may help you improve your code.

Simplify your code

This can certainly be simplified. Keep the goal in mind: get either 0 or 1 into EAX. Once you've executed this instruction:

and eax, 0x1

That's exactly what you have. So that means all of this can be deleted:

 cmp eax, 0x0 
 je print_result
 mov eax, 0x1
print_result:

And all you need to do is print the result:

call print_eax_binary