I have finally finished a Ruby calculator project, which is not based on eval. Instead it parses input char by char. The project is hosted on GitHub.
However, I find a specific part of the program very annoying since whenever I have to add something I have to rewrite a portion of it again.
def trig
case @look
when 'c'
match_all('cos')
case @look
when 'h'
match_all('h(')
value = cosh(calculate)
when '('
match('(')
value = cos(calculate)
else
expected('cos() or cosh()')
end
when 's'
match('s')
if @look == 'q'
match_all('qrt(')
value = sqrt(calculate)
else
match_all('in')
case @look
when 'h'
match_all('h(')
value = sinh(calculate)
when '('
match('(')
value = sin(calculate)
else
expected('sin() or sinh()')
end
end
when 'r'
match_all('root')
base = get_number
match('(')
value = calculate ** (1.0/base)
when 't'
match_all('tan')
case @look
when 'h'
match_all('h(')
value = tanh(calculate)
when '('
match('(')
value = tan(calculate)
else
expected('tan() or tanh()')
end
when 'l'
match('l')
case @look
when 'n'
match_all('n(')
value = log(calculate)
when 'o'
match_all('og')
if digit? @look
base = get_number
elsif @look == "("
base = 10
else
expected("integer or ( ")
end
match('(')
value = log(calculate, base)
else
expected('ln() or log()')
end
when 'e'
match_all('exp(')
value = exp(calculate)
when 'a'
match_all('arc')
case @look
when 'c'
match_all('cos')
case @look
when 'h'
match_all('h(')
value = acosh(calculate)
when '('
match('(')
value = acos(calculate)
else
expected('arccos() or arccosh()')
end
when 's'
match_all('sin')
case @look
when 'h'
match_all('h(')
value = asinh(calculate)
when '('
match('(')
value = asin(calculate)
else
expected('arcsin() or arcsinh()')
end
when 't'
match_all('tan')
case @look
when 'h'
match_all('h(')
value = atanh(calculate)
when '('
match('(')
value = atan(calculate)
else
expected('arctan() or arctanh()')
end
end
else
raise InvalidInput, "unexpected input: \"#{@look}\""
end
match(')')
value
end
The @look
variable will contain the next character. The match_all
function will simply match the input character by character. For example, it would match c
and if it works it continues to match o
and so on, but if it doesn't it will output an error.
2 Answers 2
Here's a toy program to illustrate the separation of user input collection from the string matching that determines which calc to use, as we discussed in the comments. Note that the class NamedCalculations
has no knowledge of IO with the user. All the IO is encapsulated in CmdLineCalculator
.
When I find a match, I just evaluate it with the argument pi. In your real application, you'd need to do further process to gather the user's input for the argument.
Also note how if we decide we want to change which calculations we support (one of the most likely changes for the application), it becomes a 1 line change, and the user input processing code doesn't need to be touched.
class NamedCalculations
# a hash of named calcs
# eg, {cos: Math.method(:cos), sin: Math.method(:sin) }
def initialize(calc_definitions)
@calc_definitions = calc_definitions
@calc_names = @calc_definitions.keys.map(&:to_s)
end
def method_for(calc_name)
calc_name = calc_name.to_sym
raise "Invalid Calculation Name" unless @calc_definitions.key? calc_name
@calc_definitions[calc_name]
end
def exact_match?(input)
@calc_names.any? {|name| input == name}
end
def partial_match?(input)
@calc_names.any? {|name| name.include? input}
end
end
class CmdLineCalculator
def initialize(named_calcs)
@named_calcs = named_calcs
@input = ''
end
def start
begin
system("stty raw -echo")
collect_user_input while not calc_complete?
show_answer
ensure
system("stty -raw echo")
end
end
private
def collect_user_input
@input += next_input_char
validate_input
echo_last_char
end
def validate_input
raise "Invalid Calculation" unless @named_calcs.partial_match? @input
end
def next_input_char
STDIN.getc
end
def echo_last_char
STDOUT.putc @input[-1]
end
def calc_complete?
@named_calcs.exact_match? @input
end
def show_answer
selected_method = @named_calcs.method_for(@input)
value_at_pi = selected_method.call(Math::PI)
STDOUT.puts "\nThe #{@input}(pi) = #{value_at_pi}"
end
end
my_calcs = {cos: Math.method(:cos), sin: Math.method(:sin) }
client = CmdLineCalculator.new(NamedCalculations.new(my_calcs))
client.start
Should sqrt, exp, etc. be in your Trig function? This seems to break the S in SOLID. I would abstract out your trig function and write something like:
def trig(input, val)
case input
when "sinh" return sinh(val)
when "sin" return sin(val)
when "cosh" return cosh(val)
... // cos and tans
end
end
You were right to be concerned about repeating similar pieces of code. That's something that should be avoided at all times. Coding is about being concise and minimal.
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\$\begingroup\$ The problem with this approach is that I don't know the next character . For example, if I find an s I don't know if it is sin or sqrt \$\endgroup\$Mohammad– Mohammad2015年09月20日 08:19:40 +00:00Commented Sep 20, 2015 at 8:19
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\$\begingroup\$ @Mhmd, How do you not know the next character? Does
match_all
collect user input 1 character at a time? Can you explain why it works this way? \$\endgroup\$Jonah– Jonah2015年09月21日 03:02:31 +00:00Commented Sep 21, 2015 at 3:02 -
\$\begingroup\$ @jonah yes it does that, I did this based on the "let's build a compiler" book and then added some functionality. \$\endgroup\$Mohammad– Mohammad2015年09月21日 06:32:52 +00:00Commented Sep 21, 2015 at 6:32
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\$\begingroup\$ @Mhmd, In that case the first thing you want to do is to separate the logic for matching a string to a computuation (sin, cos, etc getting mapped to their matching methods) from the user input collection. You should have one method that is collecting user input, and after each charcter is typed, it should check if there is a match yet. Does that make sense. You have the matching method responsible for collecting input. But the two things are totally separate. The matching method should know nothing about input collection. \$\endgroup\$Jonah– Jonah2015年09月21日 18:17:29 +00:00Commented Sep 21, 2015 at 18:17
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\$\begingroup\$ @Mhmd, sure, but what happens 1) if the user types something that doesn't match any calculation? 2) after the user types the open paren... eg, I type "cos(" -- now what happens? does it now collect the function's arguments? Basically, it would be easier to help with a full answer if I knew the spec of the program itself. \$\endgroup\$Jonah– Jonah2015年09月21日 18:30:52 +00:00Commented Sep 21, 2015 at 18:30