This challenge is pretty simple. As input, you take in a regular expression.
Then, you output a truthy/falsey of whether or not your source code matches the regular expression. It's that simple! Just two more things:
- No quine builtins; you may, however, access the code's source code by file IO, etc.
- This is code-golf, so shortest code in bytes wins!
Example
If your source code was say, abc
, an input of a\wc
would return true and an input of a\dc
would return false.
9 Answers 9
Z shell, 12 bytes
grep "$@"<0ドル
Zsh conditionals understand only exit codes, and the scripts exits with 0 or 1 accordingly.
In addition, this prints a non-empty string (the source code) for a match and an empty one for a mismatch, which could be as truthy/falsy values in combination with test
/[
.
The program reads its own file, but according to this comment by the OP, this is allowed.
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3\$\begingroup\$ Aaand Dennis won. ¯\_(ツ)_/¯ \$\endgroup\$Conor O'Brien– Conor O'Brien2016年01月12日 02:43:41 +00:00Commented Jan 12, 2016 at 2:43
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\$\begingroup\$ This doesn't work. It breaks on patterns with spaces in them. \$\endgroup\$feersum– feersum2016年01月12日 02:51:26 +00:00Commented Jan 12, 2016 at 2:51
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\$\begingroup\$ @feersum Whoops! Thanks for pointing that out. I have edited my answer. \$\endgroup\$Dennis– Dennis2016年01月12日 02:53:08 +00:00Commented Jan 12, 2016 at 2:53
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2\$\begingroup\$ Now it breaks if it is written to a file with spaces in the name. Or a file called
-v
. Or... \$\endgroup\$Ben Millwood– Ben Millwood2016年01月12日 15:08:50 +00:00Commented Jan 12, 2016 at 15:08 -
\$\begingroup\$ @BenMillwood I'd normally say don't save it with such a file name, but switching to zsh makes it bullet proof without incrementing the byte count. \$\endgroup\$Dennis– Dennis2016年01月12日 15:24:49 +00:00Commented Jan 12, 2016 at 15:24
JavaScript (ES6), 39
(f=_=>!!`(f=${f})()`.match(prompt()))()
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\$\begingroup\$ Just about to post this, but you beat me to it. Great job! \$\endgroup\$Mama Fun Roll– Mama Fun Roll2016年01月12日 03:29:13 +00:00Commented Jan 12, 2016 at 3:29
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12\$\begingroup\$ The beginning of your code looks like me when trying to understand this : (f=_=) \$\endgroup\$Nico– Nico2016年01月12日 09:35:54 +00:00Commented Jan 12, 2016 at 9:35
Python 3, 119 bytes
This just looks cooler, IMO (and it doesn't read the file).
(lambda i:print(bool(__import__('re').search(input(),i))))("(lambda i:print(bool(__import__('re').search(input(),i))))")
Python 3, 67 bytes
print(bool(__import__('re').search(input(),open(__file__).read())))
Added after reading this comment.
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\$\begingroup\$
int
is shorter thanbool
. \$\endgroup\$cat– cat2016年03月10日 22:42:54 +00:00Commented Mar 10, 2016 at 22:42
Julia, (削除) 64 (削除ここまで) 54 bytes
r=readline;show(ismatch(Regex(r()),open(r,@__FILE__)))
Julia regular expressions use PCRE. While reading the source code of the file is a standard loophole for quines, in this case it has been explicitly allowed. Takes input with no trailing newline.
Japt, 22 bytes
"+Q 3sAJ fU"+Q 3sAJ fU
Standard quine framework with a few bytes added to fit this challenge. Truthy = match(es), falsy = null. Try it online!
// Implicit: U = input string, A = 10, J = -1, Q = quotation mark
"..."+Q // Take this string and concatenate a quotation mark.
3 // Repeat three times.
sAJ // Slice off the first 10 and last 1 chars.
fU // Match U to the result.
Perl, 21 bytes
open 0;$_=<0>=~$_
17 bytes plus 4 bytes for -pl0
. Run like this:
echo open | perl -pl0 quinean
The source file must contain only the code above (no shebang, no trailing newline). Outputs 1
if the regex matches and the empty string if it doesn't (the empty string is falsey in Perl).
Four bytes can be saved if the input is guaranteed not to end in a newline:
open 0;say<0>=~<>
Run like this:
echo -n open | perl -M5.010 quinean
say
requires Perl 5.10+ and must be enabled with -M5.010
. According to Meta, "the -M5.010
, when needed, is free," giving a score of 17 bytes.
How it works
This is a simple variation on the standard "cheating" quine:
open 0;print<0>
This opens the file named in 0ドル
and reads the contents with <0>
.
$_=<0>=~$_
reads one line from the source file, does a regex match against the contents of $_
(which were read by the -p
flag), and assigns the result to $_
. -p
prints $_
automatically at the end.
Mathematica, 63 bytes
StringMatchQ[ToString[#0, InputForm], RegularExpression[#1]] &
Note the trailing space. Uses the standard Mma quine mechanism, and tests if it matches the regex.
Jolf, (削除) 18 (削除ここまで) 15 bytes
Supports the JS flavour of RegEx, I hope that's okay. Try it here!.
h$code.value#i
Commented:
$code.value# the document's element "code" (the program container)
_h i and output if it has (matches) the input string (i.e. regex)
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\$\begingroup\$ In which browser does this work? Both Chrome and Firefox complain that
x.step
is not a function. \$\endgroup\$Dennis– Dennis2016年01月12日 14:27:16 +00:00Commented Jan 12, 2016 at 14:27 -
\$\begingroup\$ @Dennis Huh. I must have broken the interpreter last night. What else is wrong? I currently am unable to debug, am at school. \$\endgroup\$Conor O'Brien– Conor O'Brien2016年01月12日 15:02:48 +00:00Commented Jan 12, 2016 at 15:02
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\$\begingroup\$ Good. Now add a shortcut to the document's element "code" so we can make it shorter. \$\endgroup\$user48538– user485382016年01月12日 15:26:34 +00:00Commented Jan 12, 2016 at 15:26
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\$\begingroup\$ @CᴏɴᴏʀO'Bʀɪᴇɴ It also gives a reference error for
math
. \$\endgroup\$Dennis– Dennis2016年01月12日 15:26:58 +00:00Commented Jan 12, 2016 at 15:26 -
\$\begingroup\$ @Dennis Ah, that's why. I forgot to update the HTML, I added math.js. I will revise when I arrive home, if that's not too late. (In about 4 ish hours) \$\endgroup\$Conor O'Brien– Conor O'Brien2016年01月12日 15:51:15 +00:00Commented Jan 12, 2016 at 15:51
ESMin, 14 chars / 26 bytes (non-competitive)
⟮!!(CX222+ᶈ0)đï
Using a version with bug fixes written after the challenge.
Explanation
⟮!!(CX222+ᶈ0)đï // implicit: ï=input
⟮ // copy block: copy following code for later use
(CX222+ᶈ0) // take convert 10222 to char, add stuff inside copy block
!! đï // check if input matches resulting string
// implicit output
NOTE: Copy blocks are NOT quine operators. They are meant to be more versatile alternatives to variable declarations.
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1\$\begingroup\$ I think you can save a byte by changing
X
to 10. \$\endgroup\$lirtosiast– lirtosiast2016年01月12日 05:59:42 +00:00Commented Jan 12, 2016 at 5:59
\d
is not special in BRE; it matches the characterd
. 3. Choosing a specific regex flavor restricts your challenge to languages that support it, and few languages support BRE. Is that intentional? \$\endgroup\$