How to configure 16x2 character LCD to work with 8bit?

Question

I have the LiquidCrystal library installed but all the examples are for 4bit connection, I want to drive the LCD with 8bit.

In LiquidCrystal.cpp file it says;

When the display powers up, it is configured as follows:

DL = 1; 8-bit interface data

But what's is the function, should it be like this: LiquidCrystal DL(1);? where and how should I call DL = 1;?

Answer 1

You don't "do" anything to enable 8 bit. As it says when the device powers up the DL bit in the configuration is already set, enabling 8 bit.

You just need to wire it for 8 bit and specify all 8 bits of wiring in the constructor.

The manual entry for the constructor shows you what parameters you can specify:

• https://www.arduino.cc/reference/en/libraries/liquidcrystal/liquidcrystal/