Detect if MCU is ESP8266 or ESP32

Question

I'm coding a library which handles sleep procedures.

Since I'm using both ESP826 and ESP32, which uses different sleep commands ( and WiFi ), I'm looking for a way to detect the MCU, while NOT using a boolean flag that indicates so.

Guy

• Juraj: #if defined(ESP8266), #if defined(ESP32)
• Juraj: how could you use a boolean flag? the code for esp32 would not compile on esp8266 and vice versa
• guyd: @Juraj the part that code differs, I need the flag for.
• Juraj: you have in the question "while NOT using a boolean flag that indicates so." so you exclude a not existing option

Answer 1

I take this to mean that you do not want to have to ask the user of the code to configure a boolean flag.

The ESP8266 Arduino package provides -DARDUINO_ARCH_ESP8266 -DESP8266 command-line options these while calling g++. These effectively #define feature test macros as though they were at the beginning of the source code.

For ESP32 it does likewise with -DARDUINO_ARCH_ESP32 -DESP32

You could perform tests in your code such as:

#if defined (ARDUINO_ARCH_ESP8266)
// do one thing
#elif defined(ESP32)
// do another
#else
#error Architecture unrecognized by this code.
#endif

There are likely also macros like these that are predefined by the xtensa g++ compiler.